Submission #290503

#TimeUsernameProblemLanguageResultExecution timeMemory
290503eggag32Collecting Stamps 3 (JOI20_ho_t3)C++17
0 / 100
0 ms384 KiB
#pragma GCC optimize ("O3") #pragma GCC target ("sse4") #include <bits/stdc++.h> using namespace std; typedef long long ll; typedef long double ld; typedef vector<int> vi; typedef pair<int, int> pi; #define debug(x) cerr << #x << ": " << x << endl #define debug2(x, y) debug(x), debug(y) #define repn(i, a, b) for(int i = (int)(a); i < (int)(b); i++) #define rep(i, a) for(int i = 0; i < (int)(a); i++) #define all(v) v.begin(), v.end() #define mp make_pair #define pb push_back #define lb lower_bound #define ub upper_bound #define fi first #define se second #define sq(x) ((x) * (x)) template<class T> T gcd(T a, T b){ return ((b == 0) ? a : gcd(b, a % b)); } int n, l; int solve(vector<pi> x){ int ret = 0, cnt = 0; multiset<int> st; rep(i, n) if(x[i].fi <= x[i].se){ //we keep the changes and all st.insert(x[i].se - x[i].fi); cnt++; } ret = max(ret, cnt); //equivalent to a full sweep in one direction int prev = l; int tot = 0; for(int i = n - 1; i >= 0; i--){ //we 'extend' to stamp i tot += prev - x[i].fi; if((l - x[i].fi) <= x[i].se) cnt++; if(x[i].se >= x[i].fi){ //it is already counted, but we cant sub twice cnt--; auto it = st.find(x[i].se - x[i].fi); if(it != st.end()) st.erase(it); } while(st.size() && *st.begin() < (tot * 2)){ cnt--; st.erase(st.begin()); } prev = x[i].fi; ret = max(ret, cnt); } return ret; } int main(){ ios_base::sync_with_stdio(false); cin.tie(0); //freopen("input.in", "r", stdin); //freopen("output.out", "w", stdout); cin >> n >> l; vector<pi> x(n); rep(i, n) cin >> x[i].fi; rep(i, n) cin >> x[i].se; int mx = solve(x); rep(i, n) x[i].fi = l - x[i].fi; sort(all(x)); mx = max(mx, solve(x)); cout << mx << endl; return 0; } /* Things to look out for: - Integer overflows - Array bounds - Special cases Be careful! */
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