이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <bits/stdc++.h>
using namespace std;
#define SZ(v) ((int)(v).size())
#define ALL(v) (v).begin(),(v).end()
#define one first
#define two second
typedef long long ll;
typedef pair<int, int> pi; typedef pair<ll, int> pli; typedef pair<ll, pi> plp;
typedef tuple<int, int, int> ti; typedef tuple<ll, int, int> tli;
const int INF = 0x3f2f1f0f;
const ll LINF = 1ll * INF * INF;
const int MAX_N = 2e5 + 100, MAX_M = 1e5 + 100, MAX_C = 1e9 + 100;
int N, M; ti Nr[MAX_M];
ll Sum[MAX_N], Temp[MAX_N], maxV;
bool isCan(ll use, ll lim) {
ll up = lim - use;
// printf("[%lld %lld] [up %lld]\n", use, lim, up);
ll cnt = 0;
priority_queue<pi> Q;
for(int i=0; i<=N; i++) Temp[i] = 0;
for(int i=1, j=0; i<=N; i++) {
Temp[i] += Temp[i-1];
while(j < M && get<0>(Nr[j]) == i) Q.push(pi(get<1>(Nr[j]), get<2>(Nr[j]))), j++;
ll now = Sum[i] + Temp[i];
// printf("i %d : now %lld (%lld %lld)\n", i, now, Sum[i], Temp[i]);
while(!Q.empty() && now > up) {
int y, c; tie(y, c) = Q.top(); Q.pop();
int v = min((ll)c, (now - up + 1) / 2);
Temp[i] -= 2 * v;
Temp[y] += 2 * v;
cnt += v;
now -= 2 * v;
if(c - v > 0) Q.push(pi(y, c-v));
// printf("now %lld -> %lld\n", now+v, now);
}
if(now > up) return false;
if(cnt > use) return false;
}
return true;
}
int main() {
cin >> N >> M;
for(int i=0; i<M; i++) {
int x, y, c; scanf("%d%d%d", &x, &y, &c);
if(x > y) swap(x, y);
Nr[i] = ti(x, y, c);
Sum[x] += c; Sum[y] -= c;
}
sort(Nr, Nr+M);
for(int i=1; i<=N; i++) Sum[i] += Sum[i-1], maxV = max(maxV, Sum[i]);
ll ans = -1;
for(ll l=0, r=maxV; l<=r; ) {
ll m = (l+r) >> 1;
if(isCan(maxV-m, m) || isCan(maxV-m+1, m)) ans = m, r = m-1; else l = m+1;
}
printf("%lld\n", ans);
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
arranging_tickets.cpp: In function 'int main()':
arranging_tickets.cpp:50:43: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
int x, y, c; scanf("%d%d%d", &x, &y, &c);
^
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