Submission #289482

#	Time	Username	Problem	Language	Result	Execution time	Memory
289482		_7_7_	Teams (IOI15_teams)	C++14	77 / 100	4108 ms	380052 KiB

teams

#include "teams.h"
#include <bits/stdc++.h>                                           
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
 
using namespace std;
using namespace __gnu_pbds;
 
//#define int long long
//#pragma GCC optimize("Ofast")
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4")
 
 
#define file(s) freopen(s".in","r",stdin); freopen(s".out","w",stdout);
#define fastio ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
#define all(x) x.begin(), x.end()
#define sz(s) (int)s.size()
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define s second
#define f first
 
 
 
 
typedef pair < long long, long long > pll;    
typedef pair < int, int > pii;  
typedef unsigned long long ull;         
typedef vector < pii > vpii;                                   	
typedef vector < int > vi;
typedef long double ldb;  
typedef long long ll;  
typedef double db;
 
typedef tree < int, null_type, less < int >, rb_tree_tag, tree_order_statistics_node_update > ordered_set;
 
const int inf = 1e9, maxn = 2e5 + 48, mod = 998244353, N = 5e5 + 12;
const int dx[] = {-1, 0, 1, 0}, dy[] = {0, -1, 0, 1}, block = 850;
const pii base = mp(1171, 3307), Mod = mp(1e9 + 7, 1e9 + 9);
const db eps = 1e-12, pi = acos(-1);
const ll INF = 1e18;

int n;


struct node {
	node *l, *r;
	int sum;
	node () {
		l = r = NULL;
		sum = 0;
	}

	node (int x) {
		sum = x;
		l = r = NULL;
	}

	node (node *L, node *R) {
		l = L, r = R;
		sum = (!l ? 0 : l->sum) + (!r ? 0 : r->sum);
	}
};

typedef node * pnode;
pnode root[N];

pnode build (int tl = 0, int tr = n - 1) {
	if (tl == tr)
		return new node();

	int tm = (tl + tr) >> 1;
	return new node(build(tl, tm), build(tm + 1, tr));
}

pnode update (pnode t, int pos, int x, int tl = 1, int tr = n) {
	if (tl == tr)
		return new node(t->sum + x);

	int tm = (tl + tr) >> 1;

	if (pos <= tm)
	    return new node(update(t->l, pos, x, tl, tm), t->r);
	return new node(t->l, update(t->r, pos, x, tm + 1, tr));		
}

int get (pnode t, int l, int r, int tl = 1, int tr = n) {
	if (l > r || l > tr || tl > r)
		return 0;

	if (l <= tl && tr <= r)
		return t->sum;

	int tm = (tl + tr) >> 1;
	return get(t->l, l, r, tl, tm) + get(t->r, l, r, tm + 1, tr);
}


vi g[N];
bool was[N];
int cnt[1000], pos[N];


      	
              
void init(int _n, int a[], int b[]) {
	n = _n;
	for (int i = 0; i < n; ++i)  {
		g[a[i]].pb(b[i]);          
		was[a[i]] = 1; 
	}
		
	root[0] = build();
	int j = 1;

	for (int i = 1; i <= n; ++i) {
		if (!was[i]) {
			pos[i] = pos[i - 1];
			continue;  
		}

		pos[i] = j;
		root[j] = root[j - 1];

		for (auto x : g[i])
			root[j] = update(root[j], x, 1);

		++j;
	}
}

int can(int m, int k[]) {
	int sum = 0;
	
	vpii vv;
	vi vals;

	for (int i = 0; i < m; ++i) {
		sum += k[i];
		if (sum > n)
			return 0;
		vals.pb(k[i]);
	}

	sort(all(vals));
	for (int i = 0; i < sz(vals); ) {
		int j = i, s = 0;
		while (j < sz(vals) && vals[i] == vals[j]) 
			s += vals[j++];

		vv.pb(mp(vals[i], s));		
		i = j;
	}

		
	if (m > block) {
		priority_queue < int, vi, greater < int > > q;
		int j = 0;
		for (auto x : vv) {
			while (j <= x.f) {
				for (auto b : g[j])
					if (b >= x.f)
						q.push(b);	
				++j;
			}
			
			while (sz(q) && x.s) {
				if (q.top() >= x.f)
					--x.s;
				q.pop();			
			}

			if (x.s)
				return 0;
		}
		return 1;
	}


	for (int i = 0; i < sz(vv); ++i)
		cnt[i] = 0;

//	cerr << pos[1] << ' ' << pos[2] << ' ' << pos[3] << ' ' << pos[4] << endl;
	for (int i = 0; i < sz(vv); ++i) {
		int rest = vv[i].s;
		for (int j = i; j < sz(vv); ++j) {
			if (!pos[vv[i].f])
				continue;

			int cur = get(root[pos[vv[i].f]], vv[j].f, (j == sz(vv) - 1 ? n : vv[j + 1].f - 1)) - cnt[j];
//			cerr << i << ' ' << cur << ' ' << vv[j].f << ' ' << (j == sz(vv) - 1 ? n : vv[j + 1].f - 1) << ' ' << cnt[j] << endl;
			cnt[j] += min(cur, rest);
			rest -= min(cur, rest);
			if (!rest)
				break;
		}

		if (rest)
			return 0;
	}
		

	return 1;
}

• Subtask 1: 21 / 21
• Subtask 2: 13 / 13
• Subtask 3: 43 / 43
• Subtask 4: 0 / 23