이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "teams.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
//#define int long long
//#pragma GCC optimize("Ofast")
//#pragma comment(linker, "/stack:200000000")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4")
#define file(s) freopen(s".in","r",stdin); freopen(s".out","w",stdout);
#define fastio ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
#define all(x) x.begin(), x.end()
#define sz(s) (int)s.size()
#define pb push_back
#define ppb pop_back
#define mp make_pair
#define s second
#define f first
typedef pair < long long, long long > pll;
typedef pair < int, int > pii;
typedef unsigned long long ull;
typedef vector < pii > vpii;
typedef vector < int > vi;
typedef long double ldb;
typedef long long ll;
typedef double db;
typedef tree < int, null_type, less < int >, rb_tree_tag, tree_order_statistics_node_update > ordered_set;
const int inf = 1e9, maxn = 2e5 + 48, mod = 998244353, N = 5e5 + 12;
const int dx[] = {-1, 0, 1, 0}, dy[] = {0, -1, 0, 1}, block = 450;
const pii base = mp(1171, 3307), Mod = mp(1e9 + 7, 1e9 + 9);
const db eps = 1e-12, pi = acos(-1);
const ll INF = 1e18;
int n;
struct node {
node *l, *r;
int sum;
node () {
l = r = NULL;
sum = 0;
}
node (int x) {
sum = x;
l = r = NULL;
}
node (node *L, node *R) {
l = L, r = R;
sum = (!l ? 0 : l->sum) + (!r ? 0 : r->sum);
}
};
typedef node * pnode;
pnode root[N];
pnode build (int tl = 0, int tr = n - 1) {
if (tl == tr)
return new node();
int tm = (tl + tr) >> 1;
return new node(build(tl, tm), build(tm + 1, tr));
}
pnode update (pnode t, int pos, int x, int tl = 1, int tr = n) {
if (tl == tr)
return new node(t->sum + x);
int tm = (tl + tr) >> 1;
if (pos <= tm)
return new node(update(t->l, pos, x, tl, tm), t->r);
return new node(t->l, update(t->r, pos, x, tm + 1, tr));
}
int get (pnode t, int l, int r, int tl = 1, int tr = n) {
if (l > r || l > tr || tl > r)
return 0;
if (l <= tl && tr <= r)
return t->sum;
int tm = (tl + tr) >> 1;
return get(t->l, l, r, tl, tm) + get(t->r, l, r, tm + 1, tr);
}
vi g[N];
int cnt[N];
void init(int _n, int a[], int b[]) {
n = _n;
for (int i = 0; i < n; ++i)
g[a[i]].pb(b[i]);
root[0] = build();
for (int i = 1; i <= n; ++i) {
root[i] = root[i - 1];
for (auto j : g[i])
root[i] = update(root[i], j, 1);
}
}
int can(int m, int k[]) {
int sum = 0;
vpii vv;
vi vals;
for (int i = 0; i < m; ++i) {
sum += k[i];
if (sum > n)
return 0;
vals.pb(k[i]);
}
sort(all(vals));
for (int i = 0; i < sz(vals); ) {
int j = i, s = 0;
while (j < sz(vals) && vals[i] == vals[j])
s += vals[j++];
vv.pb(mp(vals[i], s));
i = j;
}
if (m > block) {
priority_queue < int, vi, greater < int > > q;
int j = 0;
for (auto x : vv) {
while (j <= x.f) {
for (auto b : g[j])
q.push(b);
++j;
}
while (sz(q) && x.s) {
if (q.top() >= x.f)
--x.s;
q.pop();
}
if (x.s)
return 0;
}
return 1;
}
for (int i = 0; i < sz(vv); ++i)
cnt[i] = 0;
for (int i = 0; i < sz(vv); ++i) {
int rest = vv[i].s;
for (int j = i; j < sz(vv); ++j) {
int cur = get(root[vv[i].f], vv[j].f, (j == sz(vv) - 1 ? n : vv[j + 1].f - 1)) - cnt[j];
// cerr << i << ' ' << cur << ' ' << vv[j].f << ' ' << (j == sz(vv) - 1 ? n : vv[j + 1].f - 1) << ' ' << cnt[j] << endl;
cnt[j] += min(cur, rest);
rest -= min(cur, rest);
if (!rest)
break;
}
if (rest)
return 0;
}
return 1;
}
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