Submission #286466

#	Time	Username	Problem	Language	Result	Execution time	Memory
286466		YJU	Port Facility (JOI17_port_facility)	C++14	0 / 100	1 ms	384 KiB

port_facility

#include<bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<ll,ll> pll;
const ll MOD=1e9+7;
const ll MOD2=998244353;
const ll N=2e6+5;
const ld pi=3.14159265359;
const ll INF=(1LL<<60);
#define SQ(i) ((i)*(i))
#define REP(i,n) for(ll i=0;i<n;i++)
#define REP1(i,n) for(ll i=1;i<=n;i++)
#define pb push_back
#define mp make_pair
#define X first
#define Y second
#define setp setprecision
#define lwb lower_bound
#define SZ(_a) (ll)_a.size()

ll seg[3][4*N],ans=1,n,col[N];
ll r[N],l[N],x[N],y[N];
set<ll> idx;
vector<pair<pll,ll> > ed;

ll Q(ll ty,ll id,ll l,ll r,ll ql,ll qr){
	if(l>=ql&&r<=qr)return seg[ty][id];
	if(l>=qr||r<=ql)return 0;
	ll mid=(l+r)/2;
	return Q(ty,id*2,l,mid,ql,qr)+Q(ty,id*2+1,mid,r,ql,qr);
}

void ins(ll ty,ll id,ll l,ll r,ll to,ll d){
	if(l==r-1){seg[ty][id]+=d;return;}
	ll mid=(l+r)/2;
	if(to<mid){
		ins(ty,id*2,l,mid,to,d);
	}else{
		ins(ty,id*2+1,mid,r,to,d);
	}
	seg[ty][id]=seg[ty][id*2]+seg[ty][id*2+1];
}

void DFS(ll nd){
	for(ll i=*idx.lwb(x[nd]);i<y[nd];i=*idx.lwb(i+1)){
		ll tmp=max(l[i],r[i]);
		col[tmp]=3-col[nd];
		idx.erase(x[tmp]);idx.erase(y[tmp]);
		DFS(tmp);
	}
}

int main(){
	ios_base::sync_with_stdio(0);cin.tie(0);
	cin>>n;
	idx.insert(2*n+1);idx.insert(0);
	REP1(i,n)cin>>x[i]>>y[i],ed.pb(mp(mp(x[i],y[i]),i)),r[x[i]]=l[y[i]]=i,idx.insert(x[i]),idx.insert(y[i]);
	sort(ed.begin(),ed.end(),[](pair<pll,ll> a,pair<pll,ll> b){
		if(a.X.Y-a.X.X!=b.X.Y-b.X.X)return (a.X.Y-a.X.X<b.X.Y-b.X.X);
		return (a.X.X<b.X.X);
	});
	for(auto i:ed){
		if(!col[i.Y]){
			ans=ans*2%MOD;
			col[i.Y]=1;
			idx.erase(i.X.X);idx.erase(i.X.Y);
			DFS(i.Y);
		}
	}
	sort(ed.begin(),ed.end());
	for(auto i:ed){
		int ty=col[i.Y];
		if(Q(ty,1,1,2*n+1,i.X.X,i.X.Y+1)){
			cout<<"0\n";return 0;
		}
		ins(ty,1,1,2*n+1,i.X.Y,1);
	}
	cout<<ans<<"\n";
	return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 12
• Subtask 3: 0 / 56
• Subtask 4: 0 / 22