답안 #284668

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
284668 2020-08-27T21:29:04 Z Benq Ruka (COI15_ruka) C++14
100 / 100
918 ms 19832 KB
#include <bits/stdc++.h>
using namespace std;
 
typedef long long ll;
typedef long double ld;
typedef double db; 
typedef string str; 

typedef pair<int,int> pi;
typedef pair<ll,ll> pl; 
typedef pair<db,db> pd; 

typedef vector<int> vi; 
typedef vector<bool> vb; 
typedef vector<ll> vl; 
typedef vector<db> vd; 
typedef vector<str> vs; 
typedef vector<pi> vpi;
typedef vector<pl> vpl; 
typedef vector<pd> vpd; 
template<class T> using V = vector<T>; 
template<class T, size_t SZ> using AR = array<T,SZ>; 

#define mp make_pair
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) begin(x), end(x)
#define rall(x) (x).rbegin(), (x).rend() 
#define sor(x) sort(all(x)) 
#define rsz resize
#define ins insert 
#define ft front() 
#define bk back()
#define pf push_front 
#define pb push_back
#define eb emplace_back 
#define lb lower_bound 
#define ub upper_bound 

#define FOR(i,a,b) for (int i = (a); i < (b); ++i)
#define F0R(i,a) FOR(i,0,a)
#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)
#define R0F(i,a) ROF(i,0,a)
#define trav(a,x) for (auto& a: x)

const int MOD = 1e9+7; // 998244353;
const int MX = 3e5+5; 
const ll INF = 1e18; 
const ld PI = acos((ld)-1);
const int xd[4] = {1,0,-1,0}, yd[4] = {0,1,0,-1}; 
mt19937 rng((uint32_t)chrono::steady_clock::now().time_since_epoch().count()); 

template<class T> bool ckmin(T& a, const T& b) { 
	return b < a ? a = b, 1 : 0; }
template<class T> bool ckmax(T& a, const T& b) { 
	return a < b ? a = b, 1 : 0; } 
constexpr int pct(int x) { return __builtin_popcount(x); } 
constexpr int bits(int x) { return 31-__builtin_clz(x); } // floor(log2(x)) 
ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up
ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down
ll half(ll x) { return fdiv(x,2); }

template<class T, class U> T fstTrue(T lo, T hi, U f) { 
	// note: if (lo+hi)/2 is used instead of half(lo+hi) then this will loop infinitely when lo=hi
	hi ++; assert(lo <= hi); // assuming f is increasing
	while (lo < hi) { // find first index such that f is true 
		T mid = half(lo+hi);
		f(mid) ? hi = mid : lo = mid+1; 
	} 
	return lo;
}
template<class T, class U> T lstTrue(T lo, T hi, U f) {
	lo --; assert(lo <= hi); // assuming f is decreasing
	while (lo < hi) { // find first index such that f is true 
		T mid = half(lo+hi+1);
		f(mid) ? lo = mid : hi = mid-1;
	} 
	return lo;
}
template<class T> void remDup(vector<T>& v) { 
	sort(all(v)); v.erase(unique(all(v)),end(v)); }

// INPUT
template<class A> void re(complex<A>& c);
template<class A, class B> void re(pair<A,B>& p);
template<class A> void re(vector<A>& v);
template<class A, size_t SZ> void re(array<A,SZ>& a);

template<class T> void re(T& x) { cin >> x; }
void re(db& d) { str t; re(t); d = stod(t); }
void re(ld& d) { str t; re(t); d = stold(t); }
template<class H, class... T> void re(H& h, T&... t) { re(h); re(t...); }

template<class A> void re(complex<A>& c) { A a,b; re(a,b); c = {a,b}; }
template<class A, class B> void re(pair<A,B>& p) { re(p.f,p.s); }
template<class A> void re(vector<A>& x) { trav(a,x) re(a); }
template<class A, size_t SZ> void re(array<A,SZ>& x) { trav(a,x) re(a); }

// TO_STRING
#define ts to_string
str ts(char c) { return str(1,c); }
str ts(const char* s) { return (str)s; }
str ts(str s) { return s; }
str ts(bool b) { 
	#ifdef LOCAL
		return b ? "true" : "false"; 
	#else 
		return ts((int)b);
	#endif
}
template<class A> str ts(complex<A> c) { 
	stringstream ss; ss << c; return ss.str(); }
str ts(vector<bool> v) {
	str res = "{"; F0R(i,sz(v)) res += char('0'+v[i]);
	res += "}"; return res; }
template<size_t SZ> str ts(bitset<SZ> b) {
	str res = ""; F0R(i,SZ) res += char('0'+b[i]);
	return res; }
template<class A, class B> str ts(pair<A,B> p);
template<class T> str ts(T v) { // containers with begin(), end()
	#ifdef LOCAL
		bool fst = 1; str res = "{";
		for (const auto& x: v) {
			if (!fst) res += ", ";
			fst = 0; res += ts(x);
		}
		res += "}"; return res;
	#else
		bool fst = 1; str res = "";
		for (const auto& x: v) {
			if (!fst) res += " ";
			fst = 0; res += ts(x);
		}
		return res;

	#endif
}
template<class A, class B> str ts(pair<A,B> p) {
	#ifdef LOCAL
		return "("+ts(p.f)+", "+ts(p.s)+")"; 
	#else
		return ts(p.f)+" "+ts(p.s);
	#endif
}

// OUTPUT
template<class A> void pr(A x) { cout << ts(x); }
template<class H, class... T> void pr(const H& h, const T&... t) { 
	pr(h); pr(t...); }
void ps() { pr("\n"); } // print w/ spaces
template<class H, class... T> void ps(const H& h, const T&... t) { 
	pr(h); if (sizeof...(t)) pr(" "); ps(t...); }

// DEBUG
void DBG() { cerr << "]" << endl; }
template<class H, class... T> void DBG(H h, T... t) {
	cerr << ts(h); if (sizeof...(t)) cerr << ", ";
	DBG(t...); }
#ifdef LOCAL // compile with -DLOCAL, chk -> fake assert
	#define dbg(...) cerr << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__)
	#define chk(...) if (!(__VA_ARGS__)) cerr << "Line(" << __LINE__ << ") -> function(" \
		 << __FUNCTION__  << ") -> CHK FAILED: (" << #__VA_ARGS__ << ")" << "\n", exit(0);
#else
	#define dbg(...) 0
	#define chk(...) 0
#endif

// FILE I/O
void setIn(str s) { freopen(s.c_str(),"r",stdin); }
void setOut(str s) { freopen(s.c_str(),"w",stdout); }
void unsyncIO() { cin.tie(0)->sync_with_stdio(0); }
void setIO(str s = "") {
	unsyncIO();
	// cin.exceptions(cin.failbit); 
	// throws exception when do smth illegal
	// ex. try to read letter into int
	if (sz(s)) { setIn(s+".in"), setOut(s+".out"); } // for USACO
}

/**
 * Description: A set (not multiset!) with support for finding the $n$'th
 * element, and finding the index of an element. Change \texttt{null\_type} for map.
 * Time: O(\log N)
 * Source: KACTL
   * https://codeforces.com/blog/entry/11080
 * Verification: many
 */

#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
template <class T> using Tree = tree<T, null_type, less<T>, 
	rb_tree_tag, tree_order_statistics_node_update>; 
#define ook order_of_key
#define fbo find_by_order

void treeExample() {
	Tree<int> t, t2; t.insert(8);
	auto it = t.insert(10).f; assert(it == t.lb(9));
	assert(t.ook(10) == 1 && t.ook(11) == 2 && *t.fbo(0) == 8);
	t.join(t2); // assuming T < T2 or T > T2, merge t2 into t
}

/**
int atMost(Tree<pi>& T, int r) { 
	return T.ook({r,MOD}); }
int getSum(Tree<pi>& T, int l, int r) { 
	return atMost(T,r)-atMost(T,l-1); }
*/

int N,M;
vpi v, upd;
char typ[MX];
vi ans;

int cnt;

void INS(Tree<pi>& a, int x) {
	a.insert({x,cnt++});
}

void DEL(Tree<pi>& a, int x) {
	auto it = a.lb({x,0}); assert(it != end(a));
	a.erase(it);
}

struct con {
	Tree<pi> pos, neg;
	int offset = 0;
	void ins(int l, int r) {
		dbg("INS",l,r);
		if (l > r) swap(l,r);
		l -= offset, r -= offset;
		INS(pos,l), INS(neg,r);
	}
	void del(int l, int r) {
		dbg("DEL",l,r);
		if (l > r) swap(l,r);
		l -= offset, r -= offset;
		DEL(pos,l), DEL(neg,r);
	}
	int query(int x) {
		// [l+offset,r+offset] contains x 
		// x-offset
		x -= offset;
		return pos.ook({x,0})-neg.ook({x,0});
	}
};

bool ok(int l, int r) {
	if (l > r) swap(l,r);
	return l < 0 && r > 0;
}

con bef, aft;

void solve() {
	bef = aft = con();
	int pos = 0;
	FOR(i,1,N) {
		aft.ins(pos,pos+v[i].f);
		pos += v[i].f;
	}
	// dbg(aft);
	int ind = 0; pos = 0;
	F0R(i,M) {
		dbg("DOING",i,typ[i]);
		if (typ[i] == 'B') {
			if (ind == 0) continue;
			aft.offset += v[ind].f; aft.ins(0,v[ind].f);
			ind --; pos -= v[ind].f; bef.del(pos,pos+v[ind].f);
		} else if (typ[i] == 'F') {
			if (ind == N-1) continue;
			bef.ins(pos,pos+v[ind].f);
			pos += v[ind].f; ind ++;
			aft.del(0,v[ind].f); aft.offset -= v[ind].f;
		} else if (typ[i] == 'C') {
			v[ind].f = upd[i].f;
		} else {
			ans[i] += bef.query(-1);
			ans[i] += ok(1+pos,1+pos+v[ind].f);
			ans[i] += aft.query(-1-(pos+v[ind].f));
			dbg("OOPS",i,ans[i]);
		}
	}
}

int main() {
	setIO(); re(N);
	v.rsz(N); re(v);
	re(M); upd.rsz(M); ans.rsz(M);
	F0R(i,M) {
		re(typ[i]);
		if (typ[i] == 'C') re(upd[i]);
	}
	solve();
	trav(t,v) swap(t.f,t.s);
	trav(t,upd) swap(t.f,t.s);
	solve();
	F0R(i,M) if (typ[i] == 'Q') ps(ans[i]);
	// you should actually read the stuff at the bottom
}

/* stuff you should look for
	* int overflow, array bounds
	* special cases (n=1?)
	* do smth instead of nothing and stay organized
	* WRITE STUFF DOWN
	* DON'T GET STUCK ON ONE APPROACH
*/

Compilation message

ruka.cpp: In member function 'void con::insert(int, int)':
ruka.cpp:165:19: warning: statement has no effect [-Wunused-value]
  165 |  #define dbg(...) 0
      |                   ^
ruka.cpp:232:3: note: in expansion of macro 'dbg'
  232 |   dbg("INS",l,r);
      |   ^~~
ruka.cpp: In member function 'void con::del(int, int)':
ruka.cpp:165:19: warning: statement has no effect [-Wunused-value]
  165 |  #define dbg(...) 0
      |                   ^
ruka.cpp:238:3: note: in expansion of macro 'dbg'
  238 |   dbg("DEL",l,r);
      |   ^~~
ruka.cpp: In function 'void solve()':
ruka.cpp:165:19: warning: statement has no effect [-Wunused-value]
  165 |  #define dbg(...) 0
      |                   ^
ruka.cpp:268:3: note: in expansion of macro 'dbg'
  268 |   dbg("DOING",i,typ[i]);
      |   ^~~
ruka.cpp:165:19: warning: statement has no effect [-Wunused-value]
  165 |  #define dbg(...) 0
      |                   ^
ruka.cpp:284:4: note: in expansion of macro 'dbg'
  284 |    dbg("OOPS",i,ans[i]);
      |    ^~~
ruka.cpp: In function 'void setIn(str)':
ruka.cpp:170:28: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
  170 | void setIn(str s) { freopen(s.c_str(),"r",stdin); }
      |                     ~~~~~~~^~~~~~~~~~~~~~~~~~~~~
ruka.cpp: In function 'void setOut(str)':
ruka.cpp:171:29: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
  171 | void setOut(str s) { freopen(s.c_str(),"w",stdout); }
      |                      ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 3 ms 512 KB Output is correct
3 Correct 2 ms 512 KB Output is correct
4 Correct 2 ms 512 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 3 ms 512 KB Output is correct
3 Correct 2 ms 512 KB Output is correct
4 Correct 2 ms 512 KB Output is correct
5 Correct 244 ms 9080 KB Output is correct
6 Correct 130 ms 5112 KB Output is correct
7 Correct 190 ms 9464 KB Output is correct
8 Correct 209 ms 9464 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 3 ms 512 KB Output is correct
3 Correct 2 ms 512 KB Output is correct
4 Correct 2 ms 512 KB Output is correct
5 Correct 244 ms 9080 KB Output is correct
6 Correct 130 ms 5112 KB Output is correct
7 Correct 190 ms 9464 KB Output is correct
8 Correct 209 ms 9464 KB Output is correct
9 Correct 563 ms 13048 KB Output is correct
10 Correct 918 ms 19832 KB Output is correct
11 Correct 797 ms 19064 KB Output is correct
12 Correct 869 ms 19064 KB Output is correct