Submission #284396

# Submission time Handle Problem Language Result Execution time Memory
284396 2020-08-27T10:44:28 Z amiratou Ideal city (IOI12_city) C++14
23 / 100
68 ms 13688 KB
#include <bits/stdc++.h> 
using namespace std;
#define fi first
#define se second
typedef long long ll ;
#define sz(x) (ll)(x.size())
const ll MOD = (ll)(1e9),MX=(int)(1e5+5);
typedef pair<ll,ll> ii;

ll par[MX],parXY[MX];
ll ans,cnt[MX];
vector<pair<ll,ii> > vec[MX];
bitset<MX> vis;
vector<ii> vecD[2];

ii solve(ll node,ll p){
	ii h={0,cnt[node]};
	for(auto &it:vec[node])
		if(it.fi!=p){
			if(it.se.fi==-1)
				it.se=solve(it.fi,node);
			h.fi+=it.se.fi+it.se.se;
			h.se+=it.se.se;
		}
	return h;
}

ll findSet(ll i){
	if(par[i]==i)return i;
	return par[i]=findSet(par[i]);
}
ll findSetXY(ll i){
	if(parXY[i]==i)return i;
	return parXY[i]=findSet(parXY[i]);
}

void Union(ll a,ll b){
	ll x=findSet(a),y=findSet(b);
	if(x<y)swap(x,y);
	if(x!=y)par[x]=y,cnt[y]+=cnt[x];
}
bool UnionXY(ll a,ll b){
	ll x=findSetXY(a),y=findSetXY(b);
	if(x!=y){parXY[x]=y;return 1;}
	return 0;
}
void work(ll idx){
	vis=0;
	for (ll i = 0; i < sz(vecD[idx]); ++i)
		par[i]=i,parXY[i]=i,cnt[i]=1,vec[i].clear();
	for (ll i = 0; i < sz(vecD[idx]);)
	{
		ll j=i;
		while(j<sz(vecD[idx]) && vecD[idx][j].fi==vecD[idx][i].fi && (vecD[idx][i].se+(j-i))==vecD[idx][j].se){
			Union(i,j);
			ll k=lower_bound(vecD[idx].begin(),vecD[idx].end(),make_pair(vecD[idx][j].fi-1,vecD[idx][j].se))-vecD[idx].begin();
			if(k!=sz(vecD[idx]) && vecD[idx][k]==make_pair(vecD[idx][j].fi-1,vecD[idx][j].se)){
				ll a=findSet(j),b=findSet(k);
				if(UnionXY(a,b)){vec[a].push_back({b,{-1,-1}}),vec[b].push_back({a,{-1,-1}});}
			}
			j++;
		}
		i=j;
	}
	for (ll i = 0; i < sz(vecD[idx]); ++i){
		ll l=findSet(i);
		if(!vis[l])vis[l]=1,ans+=solve(l,l).fi*cnt[l];
	}
}

int DistanceSum(int N, int *X, int *Y) {
	vecD[0].resize(N),vecD[1].resize(N);
	for (ll i = 0; i < N; ++i)
		vecD[0][i]={X[i],Y[i]},vecD[1][i]={Y[i],X[i]};
	for (ll i = 0; i < 2; ++i)
		sort(vecD[i].begin(),vecD[i].end());
	work(0),work(1);
	return (int)((ans/2LL)%MOD);
}
# Verdict Execution time Memory Grader output
1 Correct 2 ms 2688 KB Output is correct
2 Correct 2 ms 2688 KB Output is correct
3 Correct 2 ms 2688 KB Output is correct
4 Incorrect 2 ms 2688 KB Output isn't correct
5 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Incorrect 3 ms 2944 KB Output isn't correct
2 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Correct 18 ms 4224 KB Output is correct
2 Correct 14 ms 4224 KB Output is correct
3 Correct 33 ms 6392 KB Output is correct
4 Correct 33 ms 6392 KB Output is correct
5 Correct 66 ms 9976 KB Output is correct
6 Correct 65 ms 9976 KB Output is correct
7 Correct 66 ms 10232 KB Output is correct
8 Correct 67 ms 9848 KB Output is correct
9 Correct 66 ms 10104 KB Output is correct
10 Correct 68 ms 13688 KB Output is correct
# Verdict Execution time Memory Grader output
1 Incorrect 19 ms 5152 KB Output isn't correct
2 Halted 0 ms 0 KB -