이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define fi first
#define se second
#define eb emplace_back
#define mt make_tuple
#define all(x) (x).begin(), (x).end()  
#define sz(x) int(x.size()) 
#define MOD 1000000007
typedef long long ll;
typedef pair <int, int> ii;
typedef pair <ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vll;
typedef long double ld;
const ll INF=63;
const int mxn=400;
bool DEBUG=0;
ll choose[mxn][mxn],dp[mxn][mxn][2];
void jia(ll &a, ll b){
	a=1ll*(a+b)%MOD;
}
ll mul(ll a, ll b){
	return 1ll*a*b%MOD;
}
ll modpow(ll a, ll b){
	ll res = 1ll;
	while(b){
		if(b&1)jia(res,a);
		mul(a,a);
		b/=2;
	}
	return res%MOD;
}
void init(){
	for(int i=0; i<mxn; i++){
		choose[i][0]=1ll;
		for(int j=1; j<=i; j++){
			choose[i][j]=(choose[i-1][j-1]+choose[i-1][j])%MOD;
		}
	}
}
int n;
int main()
{
    ios_base::sync_with_stdio(0); cin.tie(0);
    //freopen("input.txt","r",stdin); freopen("output.txt","w",stdout);
    init();
    cin>>n;
    dp[1][0][0]=dp[1][1][1]=1;
    for(int i=2; i<=n; i++)
		dp[1][i][0]=1;
    for(int i=2; i<=n; i++){
		for(int j=0; j<=n; j++){
			for(int k=0; k<=j; k++){
				if(k==i){
					jia(dp[i][j][1],mul(dp[i-1][j-k][0],choose[j][k]));
					jia(dp[i][j][1],mul(dp[i-1][j-k][1],choose[j][k]));
				}else{
					jia(dp[i][j][0],mul(dp[i-1][j-k][0],choose[j][k]));
					jia(dp[i][j][1],mul(dp[i-1][j-k][1],choose[j][k]));
				}
			}
		}
	}
	cout<<dp[n][n][1];
}
	
// READ & UNDERSTAND
// ll, int overflow, array bounds, memset(0)
// special cases (n=1?), n+1 (1-index)
// do smth instead of nothing & stay organized
// WRITE STUFF DOWN
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