답안 #282897

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
282897 2020-08-25T06:48:46 Z leaked Lutrija (COCI19_lutrija) C++14
70 / 70
192 ms 504 KB
#include<bits/stdc++.h>
using namespace std;
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp>
//
//    #pragma GCC optimize("-O3")
//    #pragma GCC optimize("no-stack-protector")
//    #pragma GCC optimize("fast-math")
//    #pragma GCC optimize("Ofast")
//    #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx")
//    #pragma GCC target("avx,avx2,fma")
//    #pragma GCC optimization ("unroll-loops")
//#define LOCAL
#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
#ifndef LOCAL
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
	*this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
#else
sim dor(const c&) { ris; }
#endif
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "
#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int>a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ll long long
typedef unsigned long long ull;
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define fast_io cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
#define all(x) x.begin(),x.end()
#define getfiles    ifstream cin("input.txt");ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (int)x.size()
#define endl "\n"
#define rall(x) x.rbegin(),x.rend()
#define len(a) (ll)a.size()
#define rep(x,l,r) for(ll x=l;x<r;x++)

using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
const ld pi=3.14159265359;
ll inf = 1e18,mod1=1e9+7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
template<typename T> bool umax(T& a, T b) {return a<b?a=b,1:0;}
template<typename T> bool umin(T& a, T b) {return b<a?a=b,1:0;}
bool is_prime(ll val){if(val==1)return 0;for(ll i=2;i<=sqrt(val);i++)if(val%i==0)return 0; return 1;}
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) { return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod : sqr(binpow(a, b / 2, mod)) % mod) : 1; }ll binmult(ll a, ll b, ll mod) { return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod : (2 * binmult(a, b / 2, mod)) % mod) : 0; }
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
const ll RR=1e4;
const ll tx[8]={1,-1,2,-2,-1,-2};
const ll ty[8]={-2,-2,-1,-1,2,1};
const char rev_to[4]={'E','W','N','S'};
const int M=1e9+3;
const int N=3e5+9;
const int ppp=73;
const int pr=3;
const int block=600;
const int OPEN=0;
const int CLOSE=1;
typedef pair<long long,int> pli;
typedef tree<pii,null_type,less<pii>,rb_tree_tag,tree_order_statistics_node_update> o_st;
auto rnd=bind(uniform_int_distribution<ll>(1,69596969),mt19937(time(0)));
void bad(){
    cout<<"-1";
    exit(0);
}
signed main(){
    fast_io;
    ll a,b;
    cin>>a>>b;
    if(a==2){
        if(is_prime(b-2)){
            cout<<2<<endl<<a<<' '<<b;
        }else if(is_prime(b+2)){
            cout<<3<<endl<<2<<' '<<b+2<<' '<<b;
        }else{
            cout<<-1;exit(0);
        }
    }else if(b==2){
        if(is_prime(a-2)){
            cout<<2<<endl<<a<<' '<<b;
        }else if(is_prime(a+2)){
            cout<<3<<endl<<a<<' '<<a+2<<' '<<2;
        }else{
            cout<<-1;exit(0);
        }
    }else{
        vector<ll>kk;kk.p_b(a);
        if(is_prime(a-2)){
            kk.p_b(2);
        }else if(is_prime(a+2)){
            kk.p_b(a+2);kk.p_b(2);
        }else{cout<<-1;exit(0);}
         if(is_prime(b-2)){
            kk.p_b(b);
        }else if(is_prime(b+2)){
            kk.p_b(b+2);
            kk.p_b(b);
        }else{cout<<-1;exit(0);}
        cout<<sz(kk)<<endl;
        for(auto &z: kk) cout<<z<<' ';
    }
    return 0;
}
/*

*/
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 1 ms 384 KB Output is correct
4 Correct 1 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 160 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 192 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 156 ms 384 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 138 ms 504 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 172 ms 504 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 127 ms 384 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 126 ms 504 KB Output is correct
2 Correct 1 ms 384 KB Output is correct
3 Correct 45 ms 384 KB Output is correct