제출 #281933

#제출 시각아이디문제언어결과실행 시간메모리
281933kevleeDreaming (IOI13_dreaming)C++17
18 / 100
342 ms26864 KiB
#include <bits/stdc++.h> #include "dreaming.h" using namespace std; #define pb push_back #define mod 1000000007 #define h1 7897897897897897 #define h2 7897466719774591 #define b1 98762051 #define b2 98765431 #define inf 1000000000 #define pi 3.1415926535897932384626 #define LMAX 9223372036854775807 #define ll long long #define fi first #define se second #define pii pair<int, int> #define pll pair<ll, ll> #define vi vector<int> #define vl vector<ll> #define vp vector<pii> #define SET(a, b) memset(a, b, sizeof(a)); #define all(x) (x).begin(), (x).end() #define FOR(i, a, b) for (int i = (a); i <= (b); i++) #define FORD(i, a, b) for (int i = (a); i >= (b); i--) int dist[100005], deg[100005], n, m, l, diameter, ans, sz; vp edges[100005]; vi v, comp; bool vis[100005], pushed[100005]; multiset <int> weight[100005]; void dfs(int x, int p) { diameter = max(diameter, dist[x]); vis[x] = true; v.pb(x); for (auto edge: edges[x]) { if (edge.fi != p) { dist[edge.fi] = dist[x] + edge.se; dfs(edge.fi, x); } } } int find_diameter(int root) { dist[root] = 0; diameter = 0; sz = 0; v.clear(); dfs(root, -1); return diameter; } void find_shortest_path() { priority_queue <pii, vector<pii>, greater<pii> > pq; for (int node: v) { if (deg[node] == 1) { pq.push({edges[node][0].se, node}); pushed[node] = true; deg[node] = 0; } } int sz = v.size(); while (sz > 2) { pii cur = pq.top(); pq.pop(); cout << cur.fi << ' ' << cur.se << endl; sz--; for (auto edge: edges[cur.se]) { deg[edge.fi]--; weight[edge.fi].erase(weight[edge.fi].find(edge.se)); if (deg[edge.fi] == 1) { //assert((int)weight[edge.fi].size() == 1); pq.push({*weight[edge.fi].begin(), edge.fi}); pushed[edge.fi] = true; } } } int tmp = inf*2; while (!pq.empty()) { pii cur = pq.top(); pq.pop(); tmp = min(tmp, find_diameter(cur.se)); } for (int node: v) { if (!pushed[node]) { tmp = min(tmp, find_diameter(node)); } } comp.pb(tmp); } int travelTime(int N, int M, int L, int u[], int v[], int t[]) { n = N; m = M; l = L; FOR(i, 0, m-1) { edges[u[i] + 1].emplace_back(v[i] + 1, t[i]); edges[v[i] + 1].emplace_back(u[i] + 1, t[i]); deg[u[i] + 1]++; deg[v[i] + 1]++; weight[u[i] + 1].insert(t[i]); weight[v[i] + 1].insert(t[i]); } FOR(i, 1, n) { if (!vis[i]) { ans = max(ans, find_diameter(i)); find_shortest_path(); } } int sz = comp.size(); sort(all(comp)); reverse(all(comp)); if (sz == 1) {} else if (sz == 2) { ans = max(ans, L + comp[0] + comp[1]); } else { ans = max(ans, L + comp[0] + comp[1]); ans = max(ans, L + L + comp[1] + comp[2]); } return ans; }
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