답안 #281824

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
281824	2020-08-23T14:12:01 Z	ACmachine	Nuclearia (CEOI15_nuclearia)	C++17	0 / 100	1000 ms	302856 KB

nuclearia

#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
template<typename T, typename U> using ordered_map = tree<T, U, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

typedef long long ll;
typedef long double ld;
typedef double db;
typedef string str;

typedef pair<int,int> pii;
typedef pair<ll,ll> pll;

typedef vector<int> vi;
typedef vector<ll> vll;
typedef vector<pii> vpii;
typedef vector<pll> vpll;
typedef vector<str> vstr;

#define FOR(i,j,k,in) for(int i=(j); i < (k);i+=in)
#define FORD(i,j,k,in) for(int i=(j); i >=(k);i-=in)
#define REP(i,b) FOR(i,0,b,1)
#define REPD(i,b) FORD(i,b,0,1)
#define pb push_back 
#define mp make_pair
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define rsz resize 

const double EPS = 1e-9;
const int MOD = 1e9+7; // 998244353;
const ll INFF = 1e18;
const int INF = 1e9;
const ld PI = acos((ld)-1);
const vi dy = {1, 0, -1, 0, -1, 1, 1, -1};
const vi dx = {0, 1, 0, -1, -1, 1, -1, 1};

#ifdef DEBUG
#define DBG if(1)
#else
#define DBG if(0)
#endif

#define dbg(x) cout << "(" << #x << " : " << x << ")" << endl;
// ostreams
template <class T, class U>
ostream& operator<<(ostream& out, const pair<T, U> &par) {out << "[" << par.first << ";" << par.second << "]"; return out;}
template <class T>
ostream& operator<<(ostream& out, const set<T> &cont) { out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template <class T, class U>
ostream& operator<<(ostream& out, const map<T, U> &cont) {out << "{"; for( const auto &x:cont) out << x << ", "; out << "}"; return out; }
template<class T>
ostream& operator<<(ostream& out, const vector<T> &v){ out << "[";  REP(i, v.size()) out << v[i] << ", ";  out << "]"; return out;}
// istreams
template<class T>
istream& operator>>(istream& in, vector<T> &v){ for(auto &x : v) in >> x; return in; }
template<class T, class U>
istream& operator>>(istream& in, pair<T, U> &p){ in >> p.ff >> p.ss; return in; }
//searches
template<typename T, typename U>
T bsl(T lo, T hi, U f){ hi++; T mid; while(lo < hi){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid+1; } return lo; }
template<typename U>
double bsld(double lo, double hi, U f, double p = 1e-9){ int r = 3 + (int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? hi = mid : lo = mid; } return (lo + hi)/2; }
template<typename T, typename U>
T bsh(T lo, T hi, U f){ lo--; T mid; while(lo < hi){ mid = (lo + hi + 1)/2; f(mid) ? lo = mid : hi = mid-1; } return lo; }
template<typename U>
double bshd(double lo, double hi, U f, double p = 1e-9){ int r = 3+(int)log2((hi - lo)/p); double mid; while(r--){ mid = (lo + hi)/2; f(mid) ? lo = mid : hi = mid; } return (lo + hi)/2; }
// some more utility functions
template<typename T>
pair<T, int> get_min(vector<T> &v){ typename vector<T> :: iterator it = min_element(v.begin(), v.end()); return mp(*it, it - v.begin());}
template<typename T>
pair<T, int> get_max(vector<T> &v){ typename vector<T> :: iterator it = max_element(v.begin(), v.end()); return mp(*it, it - v.begin());}        
template<typename T> bool ckmin(T& a, const T& b){return b < a ? a = b , true : false;}
template<typename T> bool ckmax(T& a, const T& b){return b > a ? a = b, true : false;}
struct AcAutomaton{
    int w, h;
    int n;
    vector<vll> plants;
    int q;
    vector<vll> queries;
	void read_in(){
		cin >> w >> h;
        cin >> n;
        plants.rsz(n, vll(4));
        cin >> plants;
        for(auto &x : plants){
            x[0]--; x[1]--;
        }
        cin >> q;
        queries.rsz(q, vll(4));
        cin >> queries;
        for(auto &x : queries){
            x[0]--; x[1]--; x[2]--; x[3]--;
        }
	}
    void solveNWH(){
        vector<vll> grid(w, vll(h, 0)); // different than usual
        auto bfs = [&](pii s, int a, int b){     
            // updatujem pole  grid;
            vector<vi> dist(w, vi(h, -1)); 
            queue<pii> q;
            dist[s.ff][s.ss] = 0;
            q.push(s);
            while(!q.empty()){
                pii v = q.front();
                q.pop();
                REP(sm, 8){
                    int nx = v.ff + dx[sm];
                    int ny = v.ss + dy[sm];
                    if(nx >= w || nx < 0 || ny >= h || ny < 0) continue;
                    if(dist[nx][ny] == -1) {
                        dist[nx][ny] = dist[v.ff][v.ss] + 1;
                        q.push(mp(nx, ny));
                    }
                }
            }
            REP(i, w){
                REP(j, h){
                    grid[i][j] += max(0ll, (ll)a - (ll)dist[i][j]*b);
                }
            }
        };
        REP(i, n) {
            vll plant = plants[i];
            bfs(mp(plant[0], plant[1]), plant[2], plant[3]);
        }
        cout << "-1" << endl; return;
        vector<vll> ps(w+1, vll(h+1, 0));
        FOR(i, 1, w+1, 1){
            FOR(j, 1, h+1, 1){
                ps[i][j] = ps[i-1][j] + ps[i][j-1] - ps[i-1][j-1] + grid[i-1][j-1];
            }
        } 
        /* cout << "GRID" << endl; */
        /* REP(i, w) cout << grid[i] << endl; */
        /* cout << "PS" << endl; */
        /* REP(i, w+1) cout << ps[i] << endl; */
        for(auto x : queries){
            ll sum = ps[x[2]+1][x[3]+1] - ps[x[2]+1][x[1]] - ps[x[0]][x[3]+1] + ps[x[0]][x[1]];
            /* dbg(ps[x[2]+1][x[3]+1]); */
            /* dbg(-ps[x[2]][x[1]]); */ 
            /* dbg(-ps[x[0]][x[3]]); */
            /* dbg(ps[x[0]][x[1]]); */
            ll area = (x[3] - x[1] + 1) * (x[2] - x[0] + 1);
            //dbg(mp(sum, area));
            cout << round((ld)sum/(ld)(area)) << endl;
        }
    }
    void solve_line(){
        
    }
	void solve(){
		solveNWH();
	}
};
    
int main(){
 	ios_base::sync_with_stdio(false);
 	cin.tie(NULL); cout.tie(NULL);
	int tcase = 1;
	while(tcase--){
		AcAutomaton solver;
		solver.read_in();
		solver.solve();
	}
    return 0;
}

Subtask #1
0 / 3.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1116 ms	274528 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #2
0 / 2.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1113 ms	274424 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #3
0 / 3.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1091 ms	30420 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #4
0 / 2.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1098 ms	30408 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #5
0 / 6.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1115 ms	288940 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #6
0 / 4.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1097 ms	124576 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #7
0 / 6.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1097 ms	44408 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #8
0 / 4.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1050 ms	69832 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #9
0 / 15.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1111 ms	302840 KB	Time limit exceeded

Subtask #10
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1094 ms	302856 KB	Time limit exceeded

Subtask #11
0 / 15.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1102 ms	58740 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #12
0 / 10.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1099 ms	58576 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #13
0 / 12.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1082 ms	58984 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

Subtask #14
0 / 8.0

#	결과	실행 시간	메모리	Grader output
1	Execution timed out	1089 ms	58988 KB	Time limit exceeded
2	Halted	0 ms	0 KB	-

답안 #281824

Compilation message