이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
#define endl "\n" // BRAT NASKO KUF E TOQ TRASH KOD
template<class T, class T2> bool chkmax(T &a, const T2 &b) {return (a < b) ? a = b, 1 : 0;}
typedef long long ll;
const ll MAX_N = 5e5 + 10;
ll arr[MAX_N];
ll tree[4 * MAX_N];
void upd(ll curr, ll l, ll r, ll ind, ll val) {
if(l == r && l == ind) {
chkmax(tree[curr], val);
return;
} else if(r < ind || l > ind) {return;}
ll m = (l + r) / 2ll;
upd(curr * 2, l, m, ind, val);
upd(curr * 2 + 1, m + 1, r, ind, val);
tree[curr] = max(tree[curr * 2], tree[curr * 2 + 1]);
}
ll ans(ll curr, ll l, ll r, ll ql, ll qr) {
if(ql <= l && r <= qr) {
return tree[curr];
} else if(l > qr || r < ql) {
return 0;
}
ll m = (l + r) / 2ll;
return max(ans(curr * 2, l, m, ql, qr), ans(curr * 2 + 1, m + 1, r, ql, qr));
}
ll dp[MAX_N];
int main() {
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
ll n;
cin >> n;
for(ll i = 1; i <= n; i ++) {
cin >> arr[i];
arr[i] += arr[i - 1];
}
for(ll i = 1; i <= n; i ++) {
ll curr = ans(1, 0, n, 0, i);
dp[i] = dp[curr] + 1;
ll nowWeight = arr[i] * 2 - arr[curr];
ll ind = lower_bound(arr + 1, arr + n + 1, nowWeight) - arr;
upd(1, 0, n, ind, i);
}
cout << dp[n] << endl;
}
/*NASKO E GOLQM GEI*/
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