답안 #268171

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
268171 2020-08-16T09:55:40 Z MarcoMeijer Chase (CEOI17_chase) C++14
40 / 100
4000 ms 50540 KB
#include <bits/stdc++.h>
using namespace std;
 
// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
 
// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }
 
// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }
 
//===================//
//  Added libraries  //
//===================//
 
//===================//
//end added libraries//
//===================//
 
void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}
 
 
//===================//
//   begin program   //
//===================//
 
const int MX = 3e5+1e4;
 
int n, m, mxbc;
ll p[MX];
vii adj[MX];
int a[MX], b[MX];
ll dp[MX][2];
int skip[MX][2];
int skipe[MX][2];
vector<pair<ll,int>> best[MX][2];
ll SM[MX];
 
ll getAns(int e, int bc);
void fillBest(int e, int bc) {
    int u = b[e];
    if(!best[u][bc].empty() && skip[u][bc] == -1) return;
    if(!best[u][bc].empty() && skip[u][bc] == a[e]) return;
 
    if(!best[u][bc].empty()) {
        best[u][bc].pb({getAns(skipe[u][bc], bc), skip[u][bc]});
        skip[u][bc] = -1;
    } else {
        FOR(v,adj[u]) if(v.fi != a[e]) {
            best[u][bc].pb({getAns(v.se, bc), v.fi});
        } else {
            skipe[u][bc] = v.se;
        }
 
        skip[u][bc] = a[e];
    }
    sort(all(best[u][bc]), greater<pair<ll,int>>());
    if(best[u][bc].sz > 2)
        best[u][bc].resize(2);
}
ll getAns(int e, int bc) {
    if(dp[e][bc] != -1) return dp[e][bc];
    int u=a[e], v=b[e];
 
    ll sm = SM[v] - ll(u == -1 ? 0 : p[u]);
    ll ans=sm;
    fillBest(e,  bc);
    fillBest(e, !bc);
    FOR(p,best[v][ bc]) if(p.se != u) {
        ans = max(ans,    p.fi); // go to w without placing breadcrumpts
        break;
    }
    FOR(p,best[v][!bc]) if(p.se != u) {
        ans = max(ans, sm+p.fi); // go to w with placing breadcrumpt at v
        break;
    }
 
    return dp[e][bc]=ans;
}
 
void program() {
    IN(n,mxbc);
    RE(i,n) IN(p[i]);
    RE(i,n-1) {
        IN(a[i], b[i]); a[i]--; b[i]--;
        adj[a[i]].pb({b[i],i});
        adj[b[i]].pb({a[i],i+n-1});
    }
    RE(i,n-1) a[i+n-1] = b[i];
    RE(i,n-1) b[i+n-1] = a[i];
    m = (n-1)*2;
    RE(u,n) {
        SM[u] = 0;
        FOR(v,adj[u]) SM[u] += p[v.fi];
    }
 
    RE(j,m) dp[j][0] = 0;
    RE1(i,mxbc) {
        RE(j,m) dp[j][i%2] = -1;
        RE(j,n) best[j][i%2].clear();
        RE(j,m) getAns(j,i%2);
    }
    
    ll ans = 0;
    RE(u,n-1) {
        FOR(v,adj[u]) {
            ans = max(ans, getAns(v.se,mxbc%2));
            ans = max(ans, SM[u]+getAns(v.se,(mxbc+1)%2));
        }
    }
    if(mxbc == 0) ans = 0;
    OUTL(ans);
}
# 결과 실행 시간 메모리 Grader output
1 Correct 15 ms 22272 KB Output is correct
2 Correct 17 ms 22272 KB Output is correct
3 Correct 18 ms 22272 KB Output is correct
4 Correct 17 ms 22272 KB Output is correct
5 Correct 17 ms 22272 KB Output is correct
6 Correct 17 ms 22272 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 15 ms 22272 KB Output is correct
2 Correct 17 ms 22272 KB Output is correct
3 Correct 18 ms 22272 KB Output is correct
4 Correct 17 ms 22272 KB Output is correct
5 Correct 17 ms 22272 KB Output is correct
6 Correct 17 ms 22272 KB Output is correct
7 Correct 26 ms 22528 KB Output is correct
8 Correct 17 ms 22528 KB Output is correct
9 Correct 16 ms 22400 KB Output is correct
10 Correct 26 ms 22400 KB Output is correct
11 Correct 19 ms 22400 KB Output is correct
12 Correct 17 ms 22400 KB Output is correct
# 결과 실행 시간 메모리 Grader output
1 Correct 3305 ms 46404 KB Output is correct
2 Correct 3408 ms 50540 KB Output is correct
3 Correct 1018 ms 38632 KB Output is correct
4 Correct 158 ms 41172 KB Output is correct
5 Execution timed out 4066 ms 41208 KB Time limit exceeded
6 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 15 ms 22272 KB Output is correct
2 Correct 17 ms 22272 KB Output is correct
3 Correct 18 ms 22272 KB Output is correct
4 Correct 17 ms 22272 KB Output is correct
5 Correct 17 ms 22272 KB Output is correct
6 Correct 17 ms 22272 KB Output is correct
7 Correct 26 ms 22528 KB Output is correct
8 Correct 17 ms 22528 KB Output is correct
9 Correct 16 ms 22400 KB Output is correct
10 Correct 26 ms 22400 KB Output is correct
11 Correct 19 ms 22400 KB Output is correct
12 Correct 17 ms 22400 KB Output is correct
13 Correct 3305 ms 46404 KB Output is correct
14 Correct 3408 ms 50540 KB Output is correct
15 Correct 1018 ms 38632 KB Output is correct
16 Correct 158 ms 41172 KB Output is correct
17 Execution timed out 4066 ms 41208 KB Time limit exceeded
18 Halted 0 ms 0 KB -