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답안 #268134

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
268134 2020-08-16T09:13:52 Z MarcoMeijer Chase (CEOI17_chase) C++14
40 / 100
 4000 ms 50480 KB 
#include <bits/stdc++.h>
using namespace std;

// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

// input
template<class T> void IN(T& x) {cin >> x;}
template<class H, class... T> void IN(H& h, T&... t) {IN(h); IN(t...); }

// output
template<class T1, class T2> void OUT(const pair<T1,T2>& x);
template<class T> void OUT(const T& x) {cout << x;}
template<class H, class... T> void OUT(const H& h, const T&... t) {OUT(h); OUT(t...); }
template<class T1, class T2> void OUT(const pair<T1,T2>& x) {OUT(x.fi,' ',x.se);}
template<class... T> void OUTL(const T&... t) {OUT(t..., "\n"); }
template<class H> void OUTLS(const H& h) {OUTL(h); }
template<class H, class... T> void OUTLS(const H& h, const T&... t) {OUT(h,' '); OUTLS(t...); }

//===================//
//  Added libraries  //
//===================//

//===================//
//end added libraries//
//===================//

void program();
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    program();
}


//===================//
//   begin program   //
//===================//

const int MX = 3e5+1e4;

int n, m, mxbc;
ll p[MX];
vii adj[MX];
int a[MX], b[MX];
ll dp[MX][2];
int skip[MX][2];
vector<pair<ll,ll>> best[MX][2];
ll SM[MX];

ll getAns(int e, int bc);
void fillBest(int e, int bc) {
    int u = b[e];
    if(!best[u][bc].empty() && skip[u][bc] == -1) return;
    if(!best[u][bc].empty() && skip[u][bc] == a[e]) return;

    if(!best[u][bc].empty()) {
        FOR(v,adj[u]) if(v.fi == skip[u][bc]) {
            best[u][bc].pb({getAns(v.se, bc), v.fi});
        }
        skip[u][bc] = -1;
    } else {
        FOR(v,adj[u]) if(v.fi != a[e]) {
            best[u][bc].pb({getAns(v.se, bc), v.fi});
        }
        skip[u][bc] = a[e];
    }
    sort(all(best[u][bc]), greater<pair<ll,ll>>());
    if(best[u][bc].sz > 2)
        best[u][bc].resize(2);
}
ll getAns(int e, int bc) {
    if(dp[e][bc] != -1) return dp[e][bc];
    int u=a[e], v=b[e];

    ll sm = SM[v] - ll(u == -1 ? 0 : p[u]);
    ll ans=0;
    fillBest(e, bc);
    fillBest(e, !bc);
    FOR(p,best[v][bc]) if(p.se != u) {
        ans = max(ans, p.fi); // go to w without placing breadcrumpts
    }
    FOR(p,best[v][!bc]) if(p.se != u) {
        ans = max(ans, sm+p.fi); // go to w with placing breadcrumpt at v
    }

    return dp[e][bc]=ans;
}

void program() {
    IN(n,mxbc);
    RE(i,n) IN(p[i]);
    RE(i,n-1) {
        IN(a[i], b[i]); a[i]--; b[i]--;
        adj[a[i]].pb({b[i],i});
        adj[b[i]].pb({a[i],i+n-1});
    }
    RE(i,n-1) a[i+n-1] = b[i];
    RE(i,n-1) b[i+n-1] = a[i];
    m = (n-1)*2;
    RE(i,n-1) a[i+m] = -1;
    RE(i,n-1) b[i+m] = i;
    m = (n-1)*3;
    RE(u,n) {
        SM[u] = 0;
        FOR(v,adj[u]) SM[u] += p[v.fi];
    }

    RE(j,m) dp[j][0] = 0;
    RE1(i,mxbc) {
        RE(j,m) dp[j][i%2] = -1;
        RE(j,n) best[j][i%2].clear();
        RE(j,m) getAns(j,i%2);
    }
    
    ll ans = 0;
    RE(i,n-1) ans = max(ans, getAns(i+(n-1)*2,mxbc%2));
    OUTL(ans);
}

Subtask #1
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 16 ms 22272 KB Output is correct
2 Correct 14 ms 22272 KB Output is correct
3 Correct 14 ms 22272 KB Output is correct
4 Correct 14 ms 22272 KB Output is correct
5 Correct 14 ms 22272 KB Output is correct
6 Correct 15 ms 22272 KB Output is correct

Subtask #2
20.0 / 20.0

# 결과 실행 시간 메모리 Grader output
1 Correct 16 ms 22272 KB Output is correct
2 Correct 14 ms 22272 KB Output is correct
3 Correct 14 ms 22272 KB Output is correct
4 Correct 14 ms 22272 KB Output is correct
5 Correct 14 ms 22272 KB Output is correct
6 Correct 15 ms 22272 KB Output is correct
7 Correct 28 ms 22528 KB Output is correct
8 Correct 18 ms 22528 KB Output is correct
9 Correct 15 ms 22400 KB Output is correct
10 Correct 29 ms 22400 KB Output is correct
11 Correct 21 ms 22400 KB Output is correct
12 Correct 16 ms 22400 KB Output is correct

Subtask #3
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4021 ms 50480 KB Time limit exceeded
2 Halted 0 ms 0 KB -

Subtask #4
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Correct 16 ms 22272 KB Output is correct
2 Correct 14 ms 22272 KB Output is correct
3 Correct 14 ms 22272 KB Output is correct
4 Correct 14 ms 22272 KB Output is correct
5 Correct 14 ms 22272 KB Output is correct
6 Correct 15 ms 22272 KB Output is correct
7 Correct 28 ms 22528 KB Output is correct
8 Correct 18 ms 22528 KB Output is correct
9 Correct 15 ms 22400 KB Output is correct
10 Correct 29 ms 22400 KB Output is correct
11 Correct 21 ms 22400 KB Output is correct
12 Correct 16 ms 22400 KB Output is correct
13 Execution timed out 4021 ms 50480 KB Time limit exceeded
14 Halted 0 ms 0 KB -