제출 #267061

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
267061		amoo_safar	회문 (APIO14_palindrome)	C++17	49 / 100	1079 ms	103652 KiB

palindrome

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
 
#define pb push_back
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define debug(x) cerr << #x << " : " << x << '\n'
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ld;
typedef string str;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef pair<pll, pll> node;
typedef tree<ll, null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
 
const ll Mod = 1e9 + 9;
const int Maxn = 3e5 + 10;
const int Maxk = 60;
const ll Inf = 2242545357980376863LL;
const ll Log = 20;
const ll Base = 998244353;
 
int Rank[Log][Maxn], n;
int idx[Maxn];
ll ph[Maxn], phr[Maxn], pw[Maxn];
pii a[Maxn];

vector<int> Rdx[Maxn];
vector<int> Rdx2[Maxn];

str s;
 
ll get(int l, int r){
	return (ph[r] - (ph[l]*pw[r - l] % Mod) + Mod) % Mod;
}
ll get_rev(int l, int r){
	return (phr[l] - (phr[r]*pw[r - l] % Mod) + Mod) % Mod;
}
 
int pal_range(int l, int r){
	int L = 0, R = min(n - r, l) + 1, mid;
	
	//int res = 0;
	//for(int i = 0; i < R - 1; i ++) if(s[l - 1 - i] != s[r + i]) return i;
	//return R - 1;
	
	while(L + 1 < R){
		mid = (L + R) >> 1;
		if(get(l - mid, l) == get_rev(r, r + mid)) L = mid;
		else R = mid;
	}
	return L;
}
 
int pal[Maxn];
 
 
int eq_range(int l1, int l2){
	int L = 0, R = min(n - l1, n - l2) + 1, mid;
	//for(int i = 0; i + 1 < R; i++) if(s[i + l1] != s[i + l2]) return i;
	//return R - 1;
	while(L + 1 < R){
		mid = (L + R) >> 1;
		if(get(l1, l1 + mid) == get(l2, l2 + mid)) L = mid;
		else R = mid;
	}
	return L;
}
int eq[Maxn];
 
 
int par[Maxn], sz[Maxn];
vector<int> Merge[Maxn];
vector<int> On[Maxn];
 
int get_par(int u){
	if(par[u] == u) return u;
	return par[u] = get_par(par[u]);
}
void merge(int u, int v){
	u = get_par(u); v = get_par(v);
	sz[u] += sz[v];
	par[v] = par[u];
}
 
int32_t main(){
	ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	pw[0] = 1;
	for(int i = 1; i < Maxn; i++) pw[i] = (pw[i - 1] * Base) % Mod;
	
	cin >> s;
	n = s.size();
	
	ph[0] = 0;
	for(int i = 1; i <= n; i++) ph[i] = (ph[i - 1] * Base + s[i - 1]) % Mod;
	phr[n] = 0;
	for(int i = n - 1; i >= 0; i--) phr[i] = (phr[i + 1] * Base + s[i]) % Mod;
	//cerr << get(0, 2) << " " << get(n-2, n) << '\n';
	
	for(int i = 0; i < n; i++) Rank[0][i] = s[i];
	int st;
	for(int l = 1; l < Log; l++){
		st = (1 << (l - 1));
		/*
		for(int i = 0; i < n; i++){
			a[i].F = Rank[l - 1][i];
			a[i].S = (i + st < n ? Rank[l - 1][i + st] : -1); 
		}
		*/
		for(int i = 0; i <= max(n, 200); i++) Rdx[i].clear(), Rdx2[i].clear();
		for(int i = 0; i < n; i++) Rdx[(i + st < n ? Rank[l - 1][i + st] : -1) + 1].pb(i);
		for(int j = 0; j <= max(n, 200); j++)
			for(int i : Rdx[j])
				Rdx2[Rank[l - 1][i]].pb(i);
		int po = 0;
		for(int j = 0; j <= max(n, 200); j++)
			for(int i : Rdx2[j])
				Rank[l][i] = po ++;
		/*
		for(int i = 0; i < n; i++)
			Rank[l][i] = lower_bound(a, a + n, pii(Rank[l - 1][i], (i + st < n ? Rank[l - 1][i + st] : -1) )) - a;
		*/
	}
	for(int i = 0; i < n; i++) idx[Rank[Log - 1][i]] = i;
	
	for(int i = 0; i < n - 1; i++) eq[i] = eq_range(idx[i], idx[i + 1]);
	for(int i = 0; i < n - 1; i++) Merge[eq[i]].pb(i);
	
	ll ans = 0;
	
	for(int i = 0; i < n; i++) pal[i] = pal_range(i + 1, i);
	for(int i = 0; i < n; i++) On[pal[i]].pb(Rank[Log - 1][i]);
	
	
	iota(par, par + Maxn, 0);
	fill(sz, sz + Maxn, 0);
	int mx = 0;
	for(int x = n + 1; x >= 1; x--){
		for(auto y : Merge[x]){
			merge(y, y + 1);
			mx = max(mx, sz[get_par(y)]);
		}
		for(auto y : On[x]){
			sz[get_par(y)] ++;
			mx = max(mx, sz[get_par(y)]);
		}
		ans = max(ans, 1LL * mx * (x + x - 1));
	}
	
	for(int i = 0; i < n; i++) pal[i] = pal_range(i, i);
	for(int i = 0; i < Maxn; i++) On[i].clear();
	for(int i = 0; i < Maxn; i++) On[pal[i]].pb(Rank[Log - 1][i]);
	
	iota(par, par + Maxn, 0);
	fill(sz, sz + Maxn, 0);
	mx = 0;
	for(int x = n + 1; x >= 1; x--){
		for(auto y : Merge[x]){
			merge(y, y + 1);
			mx = max(mx, sz[get_par(y)]);
		}
		for(auto y : On[x]){
			sz[get_par(y)] ++;
			mx = max(mx, sz[get_par(y)]);
		}
		ans = max(ans, 1LL * mx * (x + x));
	}
	
	cout << ans << '\n';;
	return 0;
}
 
/*
abacaba
 
*/

• Subtask 1: 8 / 8
• Subtask 2: 15 / 15
• Subtask 3: 0 / 24
• Subtask 4: 26 / 26
• Subtask 5: 0 / 27