제출 #266887

#제출 시각아이디문제언어결과실행 시간메모리
266887youssefbou62Linear Garden (IOI08_linear_garden)C++14
70 / 100
379 ms65540 KiB
        #include <bits/stdc++.h>
        #pragma GCC optimize("Ofast")
        #pragma GCC target("avx,avx2,fma")
        using namespace std;

        #define mp make_pair
        #define fi first
        #define se second
        #define all(v) v.begin(),v.end()
        #define allarr(a) a , a + n
        #define ll long long
        #define pb push_back
        #define fastio ios_base::sync_with_stdio(false) ; cin.tie(NULL); cout.tie(NULL)
        #define sz(x) (int)x.size()
        typedef pair<int, int> pi;
        typedef pair<ll,ll> pll ;
        typedef pair<int,pi> trp ;
        typedef vector<pi> vpi;
        typedef priority_queue< pi, vector <pi> , greater<pi> > spq;

        const int MAXN = 1e6+5 ;

        int dp[MAXN][2][5][5][5];
        int N ;
        ll M ;
        string s;
        void add(int& x ,int y ){
            x = ( x % M + y % M ) % M ;
        }

        void solve (){
            vector<int> S ;
            for(int i = 0 ; i < N ; i++ )S.pb(s[i]=='P');
            dp[0][0][2][2][2] = 1 ;
            for(int i = 0 ; i < N ; i++ ){
                for(int pref = -2 ; pref <= 2 ; pref++ )
                    for(int hpref = -2 ; hpref <= 2 ; hpref++ )
                        for(int lpref = -2 ; lpref <= 2 ; lpref++ ){
                            for(int choice : {0,1}){
                                        int nxt_pref = pref  ;
                                        if( choice )nxt_pref++;else nxt_pref--;
                                        int x = min(nxt_pref,lpref) ;
                                        int y= max(nxt_pref,hpref);
                                        if( abs(hpref-lpref) > 2 || nxt_pref==3 || nxt_pref==-3||x == -3 || y == 3 || y == -3 || x == 3 )continue ;

                                        if(choice < S[i])
                                            add(dp[i+1][1][2+nxt_pref][2+x][2+y],dp[i][0][pref+2][lpref+2][hpref+2]);
                                        if(choice == S[i])
                                            add(dp[i+1][0][2+nxt_pref][2+x][2+y],dp[i][0][pref+2][lpref+2][hpref+2]);
                                        add(dp[i+1][1][2+nxt_pref][2+x][2+y],dp[i][1][pref+2][lpref+2][hpref+2]);
                            }
                        //    if(dp[i][1][pref][lpref][hpref])
                         //   cout << i << " " << pref << " " <<lpref << " " <<hpref<<endl;
                        }
            }

            int ans = 1 ;

            for(int pref = -2 ; pref <= 2 ; pref++ )
                for(int hpref = -2 ; hpref <= 2 ; hpref++ )
                    for(int lpref = -2 ; lpref <= 2 ; lpref++)
                        if( abs(hpref-lpref) <= 2 )
                            add(ans,dp[N][1][pref+2][lpref+2][hpref+2]);
            cout << ans << endl;
        }
        int main(){
          //  ifstream cin("in.in");
            cin >> N >> M >> s ;
            solve() ;
        }
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