제출 #263541

#	제출 시각UTC-0	아이디	문제	언어	결과	실행 시간	메모리
263541	2020-08-13 19:15:10	patrikpavic2	Bitaro, who Leaps through Time (JOI19_timeleap)	C++17	100 / 100	1167 ms	86408 KiB

timeleap

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#include <cstdio>
#include <cstring>
#include <algorithm>
#define X first
#define Y second
#define PB push_back
using namespace std;
typedef pair < int, int > pii;
typedef long long ll;
const int OFF = (1 << 19);
const int INF = 0x3f3f3f3f;
struct node{
  int f_t1, f_t2, c_t;
  int c_p, nula;
  ll f_p;
  node(){
    f_t1 = 0, f_t2 = INF, c_t = 0;
    c_p = INF, f_p = 0; nula = 0;
  }
  node(int s, int t){
    f_t1 = s + 1, f_t2 = t, c_t = s;
    f_p = 0, c_p = t - 1; nula = 0;
  }
  int get_time(int s_t){
    return min(f_t2, f_t1 + max(0, s_t - c_t));
 
 
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컴파일 시 표준 에러 (stderr) 메시지

timeleap.cpp: In function 'int main()':
timeleap.cpp:93:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   93 |  scanf("%d%d", &n, &q);
      |  ~~~~~^~~~~~~~~~~~~~~~
timeleap.cpp:95:18: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   95 |   int x, y; scanf("%d%d", &x, &y);
      |             ~~~~~^~~~~~~~~~~~~~~~
timeleap.cpp:99:16: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   99 |   int ty; scanf("%d", &ty);
      |           ~~~~~^~~~~~~~~~~
timeleap.cpp:101:22: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  101 |    int p, x, y; scanf("%d%d%d", &p, &x, &y);
      |                 ~~~~~^~~~~~~~~~~~~~~~~~~~~~
timeleap.cpp:105:29: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  105 |    int l, l_t, r, r_t; scanf("%d%d%d%d", &l,&l_t, &r, &r_t);
      |                        ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 4 / 4
• Subtask 2: 30 / 30
• Subtask 3: 66 / 66