이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
using namespace std;
#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)
#define rando mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())
#define fi first
#define se second
#define debug(x) cerr << " - " << #x << ": " << x << endl;
#define debugs(x, y) cerr << " - " << #x << ": " << x << " " << #y << ": " << y << endl;
#define debugii(x) cerr << " - " << #x << ": " << x.fi<<","<<x.se << endl;
#define sep() cerr << "--------------------" << endl;
#define all(x) (x).begin(),(x).end()
#define sz(x) (ll)x.size()
#define ld long double
#define ll long long
//#define int ll
#define ii pair<int,int>
#define v vector<int>
#define vii vector<ii>
#define vv vector<vector<int> >
#define mp make_pair
#define INF 1000000000
#define pb push_back
#define EPS 1e-9
const int MOD = 1000000007; // 998244353
const int MX = 200001;
string S;
int n,m,dp[MX][16][5];
int solve(int idx,int mask,int cnt){
if(idx==n)return 1;
if(dp[idx][mask][cnt]!=-1)
return dp[idx][mask][cnt];
int h=cnt-2,ans=0;
if((h+1) <=2){
h++;
if((h==2) && !(((mask>>2)&1)|((mask>>3)&1)))ans=(ans+solve(idx+1,mask|(1<<0),h+2))%m;
if((h==1) && !((mask>>3)&1))ans=(ans+solve(idx+1,mask|(1<<1),h+2))%m;
if(h==0)ans=(ans+solve(idx+1,mask,h+2))%m;
if((h==-1) && !((mask>>0)&1))ans=(ans+solve(idx+1,mask|(1<<2),h+2))%m;
if((h==-2) && !(((mask>>0)&1)|((mask>>1)&1)))ans=(ans+solve(idx+1,mask|(1<<3),h+2))%m;
h--;
}
if((h-1) >=-2){
h--;
if((h==2) && !(((mask>>2)&1)|((mask>>3)&1)))ans=(ans+solve(idx+1,mask|(1<<0),h+2))%m;
if((h==1) && !((mask>>3)&1))ans=(ans+solve(idx+1,mask|(1<<1),h+2))%m;
if(h==0)ans=(ans+solve(idx+1,mask,h+2))%m;
if((h==-1) && !((mask>>0)&1))ans=(ans+solve(idx+1,mask|(1<<2),h+2))%m;
if((h==-2) && !(((mask>>0)&1)|((mask>>1)&1)))ans=(ans+solve(idx+1,mask|(1<<3),h+2))%m;
h++;
}
return dp[idx][mask][cnt]=ans;
}
int32_t main(){
boost;
//freopen(".in","r",stdin);
memset(dp,-1,sizeof dp);
cin>>n>>m>>S;
int ans=0,cnt=0,mask=0;
for (int i = 0; i < n; ++i){
if((S[i]=='P') && ((cnt+1)<=2)){
cnt++;
if((cnt==2) && !(((mask>>2)&1)|((mask>>3)&1)))ans=(ans+solve(i+1,mask|(1<<0),cnt+2))%m;
if((cnt==1) && !((mask>>3)&1))ans=(ans+solve(i+1,mask|(1<<1),cnt+2))%m;
if(cnt==0)ans=(ans+solve(i+1,mask,cnt+2))%m;
if((cnt==-1) && !((mask>>0)&1))ans=(ans+solve(i+1,mask|(1<<2),cnt+2))%m;
if((cnt==-2) && !(((mask>>0)&1)|((mask>>1)&1)))ans=(ans+solve(i+1,mask|(1<<3),cnt+2))%m;
cnt--;
}
cnt+=((S[i]=='P')?-1:1);
if(cnt==-1)mask|=(1<<2);
else if(cnt==1)mask|=(1<<1);
else if(cnt==2)mask|=(1<<0);
else if(cnt==-2)mask|=(1<<3);
}
cout<<(ans+1)%m<<"\n";
return 0;
}
//do smth instead of nothing and stay organized
//long long
//array bounds
//special cases
//binary search
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