oj.uz

답안 #262904

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
262904 2020-08-13T10:49:14 Z shayan_p 코알라 (APIO17_koala) C++14
33 / 100
 162 ms 516 KB 
// And you curse yourself for things you never done

#include<bits/stdc++.h>
#include "koala.h"

#define F first
#define S second
#define PB push_back
#define sz(s) int((s).size())
#define bit(n,k) (((n)>>(k))&1)

using namespace std;

typedef long long ll;
typedef pair<int,int> pii;

const int maxn = 110, mod = 1e9 + 7, inf = 1e9 + 10;

int minValue(int N, int W) {
    int A[maxn], B[maxn];
    memset(A, 0, sizeof A);
    memset(B, 0, sizeof B);
    A[0] = 1;
    playRound(A, B);
    if(B[0] <= 1)
	return 0;
    int ans = 0;
    for(int i = 1; i < N; i++)
	if(B[i] == 0)
	    ans = i;
    return ans;
}

int maxValue(int N, int W) {
    int SM[maxn];
    vector<pii> v[maxn];
    int h[maxn];
    pii pr[maxn];

    memset(SM, 0, sizeof SM);
    memset(h, -1, sizeof h);
    for(int i = 0; i < maxn; i++)
	v[i].clear();
    
    for(int i = 1; i <= N; i++)
	SM[i] = SM[i-1] + i;

    auto f = [&](int n, int cost, int top, int lim){
		 assert(top <= n);
		 int sm = 0, bst = 0;
		 for(int i = 0; i <= top; i++){
		     if(i * cost > lim)
			 break;
		     bst = max(bst, sm + SM[n-top] - SM[max(int(0), n-top-(lim - i*cost))]);
		     sm+= n-i;
		 }
		 sm = 0;
		 int bstid = -1;
		 for(int i = 0; i <= top; i++){
		     if(i * cost > lim)
			 break;
		     int num = sm + SM[n-top] - SM[max(int(0), n-top-(lim - i*cost))];
		     if(num == bst){
			 if(bstid == -1)
			     bstid = i;
			 if(bstid != i)
			     return -1;
		     }
		     sm+= n-i;
		 }
		 return bstid;
	     };

    
    for(int top = 100; top >= 1; top--){
	for(int cost = 2; top * (cost-1) <= 100; cost++){
	    int x =  f(100, cost, top, 100);
	    if(x != -1)
		v[top].PB({x, cost});
	}
    }

    queue<int> q;
    h[N] = 0;
    q.push(N);
    while(sz(q)){
	int u = q.front();
	q.pop();
	for(pii p : v[u])
	    if(h[p.F] == -1)
		pr[p.F] = {u, p.S}, h[p.F] = h[u] + 1, q.push(p.F);
    }

    vector<pii> tdo;
    int tmp = 1;
    while(tmp != N){
	tdo.PB(pr[tmp]);
	tmp = pr[tmp].F;
    }
    reverse(tdo.begin(), tdo.end());

    vector<int> big;
    for(int i = 0; i < N; i++){
	big.PB(i);
    }

    int A[maxn], B[maxn];
    bool inside[maxn];
    for(pii p : tdo){
	memset(A, 0, sizeof A);
	memset(B, 0, sizeof B);
	memset(inside, 0, sizeof inside);
	for(int id : big)
	    A[id] = p.S-1, inside[id] = 1;
	playRound(A, B);
	big.clear();
	for(int i = 0; i < N; i++){
	    if(inside[i] && B[i] >= p.S)
		big.PB(i);
	}
    }
    assert(sz(big) == 1);
    return big[0];
}

int greaterValue(int N, int W) {
    int A[maxn], B[maxn];
    for(int d : {1, 3, 5, 9}){
	memset(A, 0, sizeof A);
	memset(B, 0, sizeof B);
	A[0] = d, A[1] = d;
	playRound(A, B);
	bool X = B[0] > d, Y = B[1] > d;
	if(X ^ Y){
	    if(X)
		return 0;
	    else
		return 1;
	}
    }
    assert(0);
}

void allValues(int N, int W, int *P) {
    if (W == 2*N) {
        // TODO: Implement Subtask 4 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    } else {
        // TODO: Implement Subtask 5 solution here.
        // You may leave this block unmodified if you are not attempting this
        // subtask.
    }
}

Subtask #1
4.0 / 4.0

# 결과 실행 시간 메모리 Grader output
1 Correct 6 ms 384 KB Output is correct
2 Correct 6 ms 384 KB Output is correct
3 Correct 6 ms 384 KB Output is correct
4 Correct 6 ms 384 KB Output is correct

Subtask #2
15.0 / 15.0

# 결과 실행 시간 메모리 Grader output
1 Correct 25 ms 384 KB Output is correct
2 Correct 24 ms 384 KB Output is correct
3 Correct 28 ms 384 KB Output is correct
4 Correct 26 ms 512 KB Output is correct

Subtask #3
14.0 / 18.0

# 결과 실행 시간 메모리 Grader output
1 Partially correct 155 ms 516 KB Output is partially correct
2 Partially correct 156 ms 512 KB Output is partially correct
3 Partially correct 155 ms 512 KB Output is partially correct
4 Partially correct 152 ms 384 KB Output is partially correct
5 Partially correct 156 ms 384 KB Output is partially correct
6 Partially correct 162 ms 504 KB Output is partially correct
7 Partially correct 156 ms 512 KB Output is partially correct
8 Partially correct 154 ms 384 KB Output is partially correct
9 Partially correct 155 ms 384 KB Output is partially correct
10 Partially correct 162 ms 504 KB Output is partially correct

Subtask #4
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 256 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
0 / 53.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 0 ms 256 KB Output isn't correct
2 Halted 0 ms 0 KB -