제출 #262503

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
262503		ToMmyDong	가로등 (APIO19_street_lamps)	C++11	0 / 100	77 ms	4984 KiB

street_lamps

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<int, ll> pil;
typedef pair<ll, int> pli;
typedef pair<double, double> pdd;
#define SQ(i) ((i)*(i))
#define MEM(a, b) memset(a, (b), sizeof(a))
#define SZ(i) static_cast<int>(i.size())
#define FOR(i, j, k, in) for (int i=j; i < (k) ; i+=in)
#define RFOR(i, j, k, in) for (int i=j; i >= (k) ; i-=in)
#define REP(i, j) FOR(i, 0, j, 1)
#define REP1(i, j) FOR(i, 1, j+1, 1)
#define RREP(i, j) RFOR(i, j, 0, 1)
#define ALL(_a) _a.begin(), _a.end()
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define X first
#define Y second
template<typename T, typename S>
istream &operator >> (istream &is, pair<T, S> &p) {
    return is >> p.X >> p.Y;
}
#ifdef tmd
#define TIME(i) Timer i(#i)
#define debug(...) do {\
    fprintf(stderr, "%s - %d (%s) = ", __PRETTY_FUNCTION__, __LINE__, #__VA_ARGS__);\
    _do(__VA_ARGS__);\
}while(0)
template<typename T> void _do(T &&_x) {cerr<<_x<<endl;}
template<typename T,typename ...S> void _do(T &&_x, S &&..._t) {cerr <<_x <<" ,"; _do(_t...);}
template<typename _a,typename _b> ostream& operator << (ostream &_s, const pair<_a, _b> &_p) {return _s << "(" << _p.X << "," << _p.Y << ")";}
template<typename It> ostream& _OUTC(ostream &_s, It _ita, It _itb)
{
    _s << "{";
    for (It _it=_ita; _it != _itb; _it++) {
        _s <<(_it == _ita?"":",")<< *_it;
    }
    _s << "}";
    return _s;
}
template<typename _a> ostream &operator << (ostream &_s, const vector<_a> &_c) {return _OUTC(_s,ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,2> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,3> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,4> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,5> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const set<_a> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const deque<_a> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a,typename _b> ostream &operator << (ostream &_s, const map<_a,_b> &_c) {return _OUTC(_s,ALL(_c));}
template<typename _t> void pary(_t _a,_t _b){_OUTC(cerr,_a,_b);cerr<<endl;}
#define IOS()
class Timer {
private:
    string scope_name;
    chrono::high_resolution_clock::time_point start_time;
public:
    Timer (string name) : scope_name(name) {
        start_time = chrono::high_resolution_clock::now();
    }
    ~Timer () {
        auto stop_time = chrono::high_resolution_clock::now();
        auto length = chrono::duration_cast<chrono::microseconds>(stop_time - start_time).count();
        double mlength = double(length) * 0.001;
        debug(scope_name, mlength);
    }
};
#else
#define TIME(i)
#define debug(...)
#define pary(...)
#define endl '\n'
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0)
#endif

const ll MOD = 1000000007;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const int iNF = 0x3f3f3f3f;
const ll MAXN = 3e5 + 5;

int n, q;

bool a[MAXN];
int lst[MAXN], sum[MAXN];
signed main () {
    TIME(main);
    IOS();
    cin >> n >> q;
    for (int i=0; i<n; i++) {
        char c;
        cin >> c;
        a[i] = c == '1';
        lst[i] = 0;
    }

    for (int i=1; i<=q; i++) {
        string str;
        cin >> str;
        if (str[0] == 'q') {
            int L, R;
            cin >> L >> R;
            L--, R--;
            cout << sum[L] + a[L] * (i - lst[L]) << endl;
        } else {
            int x;
            cin >> x;
            x--;

            if (a[x]) {
                sum[x] += i - lst[i];
            } else {
                lst[x] = i;
            }
            a[x] ^= 1;
        }

    }
    
    return 0;
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 20
• Subtask 5: 0 / 20