Submission #262496

#	Time	Username	Problem	Language	Result	Execution time	Memory
262496		ToMmyDong	Bridges (APIO19_bridges)	C++11	16 / 100	336 ms	3704 KiB

bridges

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<int, ll> pil;
typedef pair<ll, int> pli;
typedef pair<double, double> pdd;
#define SQ(i) ((i)*(i))
#define MEM(a, b) memset(a, (b), sizeof(a))
#define SZ(i) static_cast<int>(i.size())
#define FOR(i, j, k, in) for (int i=j; i < (k) ; i+=in)
#define RFOR(i, j, k, in) for (int i=j; i >= (k) ; i-=in)
#define REP(i, j) FOR(i, 0, j, 1)
#define REP1(i, j) FOR(i, 1, j+1, 1)
#define RREP(i, j) RFOR(i, j, 0, 1)
#define ALL(_a) _a.begin(), _a.end()
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define X first
#define Y second
template<typename T, typename S>
istream &operator >> (istream &is, pair<T, S> &p) {
    return is >> p.X >> p.Y;
}
#ifdef tmd
#define TIME(i) Timer i(#i)
#define debug(...) do {\
    fprintf(stderr, "%s - %d (%s) = ", __PRETTY_FUNCTION__, __LINE__, #__VA_ARGS__);\
    _do(__VA_ARGS__);\
}while(0)
template<typename T> void _do(T &&_x) {cerr<<_x<<endl;}
template<typename T,typename ...S> void _do(T &&_x, S &&..._t) {cerr <<_x <<" ,"; _do(_t...);}
template<typename _a,typename _b> ostream& operator << (ostream &_s, const pair<_a, _b> &_p) {return _s << "(" << _p.X << "," << _p.Y << ")";}
template<typename It> ostream& _OUTC(ostream &_s, It _ita, It _itb)
{
    _s << "{";
    for (It _it=_ita; _it != _itb; _it++) {
        _s <<(_it == _ita?"":",")<< *_it;
    }
    _s << "}";
    return _s;
}
template<typename _a> ostream &operator << (ostream &_s, const vector<_a> &_c) {return _OUTC(_s,ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,2> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,3> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,4> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const array<_a,5> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const set<_a> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a> ostream &operator << (ostream &_s, const deque<_a> &_c) {return _OUTC(_s, ALL(_c));}
template<typename _a,typename _b> ostream &operator << (ostream &_s, const map<_a,_b> &_c) {return _OUTC(_s,ALL(_c));}
template<typename _t> void pary(_t _a,_t _b){_OUTC(cerr,_a,_b);cerr<<endl;}
#define IOS()
class Timer {
private:
    string scope_name;
    chrono::high_resolution_clock::time_point start_time;
public:
    Timer (string name) : scope_name(name) {
        start_time = chrono::high_resolution_clock::now();
    }
    ~Timer () {
        auto stop_time = chrono::high_resolution_clock::now();
        auto length = chrono::duration_cast<chrono::microseconds>(stop_time - start_time).count();
        double mlength = double(length) * 0.001;
        debug(scope_name, mlength);
    }
};
#else
#define TIME(i)
#define debug(...)
#define pary(...)
#define endl '\n'
#define IOS() ios_base::sync_with_stdio(0);cin.tie(0)
#endif

const ll MOD = 1000000007;
const ll INF = 0x3f3f3f3f3f3f3f3f;
const int iNF = 0x3f3f3f3f;
const ll MAXN = 5e4 + 5;


int zkw[MAXN*2];
int q, n, m;

void build () {
    for (int i=n-1; i>0; i--) {
        zkw[i] = min(zkw[i<<1], zkw[i<<1|1]);
    }
}

void chg (int x, int val) {
    for (zkw[x+=n]=val; x>1; x>>=1) {
        zkw[x>>1] = min(zkw[x], zkw[x^1]);
    }
}

int qry (int l, int r) {
    int ret = MOD;
    for (l+=n,r+=n; l<r; l>>=1, r>>=1) {
        if (l&1) {
            ret = min(ret, zkw[l++]);
        }
        if (r&1) {
            ret = min(ret, zkw[--r]);
        }
    }
    return ret;
}
signed main () {
    TIME(main);
    IOS();

    cin >> n >> m;
    for (int i=0; i<m; i++) {
        int u, v, w;
        cin >> u >> v >> w;
        zkw[i+n] = w;
    }
    build();

    for (cin>>q; q>0; q--) {
        int t, x, y;
        cin >> t >> x >> y;
        if (t == 1) {
            chg(x-1, y);
        } else {
            int ans = 1;
            x--;
            {
                int l = -1, r = x;
                while (l < r - 1) {
                    int m = (l + r) >> 1;
                    if (qry(m, x) < y) {
                        l = m;
                    } else {
                        r = m;
                    }
                }
                ans += x - r;
            }
            {
                int l = x, r = n;
                while (l < r - 1) {
                    int m = (l + r) >> 1;
                    if (qry(x, m) < y) {
                        r = m;
                    } else {
                        l = m;
                    }
                }
                ans += l - x;
            }
            cout << ans << endl;
        }
    }
    return 0;
}

• Subtask 1: 0 / 13
• Subtask 2: 16 / 16
• Subtask 3: 0 / 17
• Subtask 4: 0 / 14
• Subtask 5: 0 / 13
• Subtask 6: 0 / 27