이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "rect.h"
#include <vector>
#include <cmath>
#include <iostream>
#define sz(a) (a.size())
using namespace std;
int spr[705][10][705];
int spc[705][10][705];
int lg[705];
int query_r(int row, int l, int r){
int logo = lg[r-l+1];
return max(spr[row][logo][l],spr[row][logo][r-(1<<logo)+1]);
}
int query_c(int col, int l, int r){
int logo = lg[r-l+1];
return max(spc[col][logo][l],spc[col][logo][r-(1<<logo)+1]);
}
long long count_rectangles(vector<vector<int>> a) {
for (int i = 1; i < 705; ++i){
lg[i] = log2(i);
}
int n = sz(a);
int m = sz(a[0]);
int answer = 0;
for (int i = 0; i < n; ++i){
for (int j = 0; j < m; ++j){
spr[i][0][j] = a[i][j];
}
for (int k = 1; k < 10; ++k){
for (int j = 0; j < m-(1<<k)+1; ++j){
spr[i][k][j] = max(spr[i][k-1][j], spr[i][k-1][j+(1<<(k-1))]);
}
}
}
for (int i = 0; i < m; ++i){
for (int j = 0; j < n; ++j){
spc[i][0][j] = a[j][i];
}
for (int k = 1; k < 10; ++k){
for (int j = 0; j < n-(1<<k)+1; ++j){
spc[i][k][j] = max(spc[i][k-1][j], spc[i][k-1][j+(1<<(k-1))]);
}
}
}
for (int r1 = 1; r1 < n-1; ++r1){
for (int c1 = 1; c1 < m-1; ++c1){
for (int r2 = r1; r2 < n-1; ++r2){
if(a[r2][c1] >= a[r2][c1-1] ||
a[r2][c1] >= a[r1-1][c1]){
break;
}
bool milhem = false;
for (int c2 = c1; c2 < m-1 && !milhem; ++c2){
bool good = true;
for (int i = r1; i <= r2 && good; ++i){
int mx = query_r(i, c1, c2);
if(mx >= a[i][c1-1]){
good = false;
milhem = true;
}
if(mx >= a[i][c2+1]){
good = false;
}
}
for (int i = c1; i <= c2 && good; ++i){
int mx = query_c(i, r1, r2);
if(mx >= a[r1-1][i] || mx >= a[r2+1][i]){
good = false;
milhem = true;
}
}
if(good){
answer++;
}
}
}
}
}
return answer;
}
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