이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define double long double
using pii = pair<int, int>;
template<typename T>
using prior = priority_queue<T, vector<T>, greater<T>>;
template<typename T>
using Prior = priority_queue<T>;
#define X first
#define Y second
#define ALL(x) (x).begin(), (x).end()
#define eb emplace_back
#define pb push_back
#define fastIO() ios_base::sync_with_stdio(false), cin.tie(0)
const int maxn = 1E5 + 5;
vector<int> p(maxn), sz(maxn, 1);
int R(int x) {return x ^ p[x] ? p[x] = R(p[x]) : x;}
void U(int x, int y) {if (R(x) ^ R(y)) sz[R(y)] += sz[R(x)], p[R(x)] = R(y);}
int32_t main() {
fastIO();
iota(ALL(p), 0);
int n, m, ans = 0;
cin >> n >> m;
int u[m], v[m];
for (int i = 0; i < m; ++i) {
cin >> u[i] >> v[i], U(u[i], v[i]);
}
map<int, int> cnt;
for (int i = 0; i < m; ++i) {
++cnt[R(u[i])];
}
for (auto [idx, val] : cnt) {
if (val == sz[idx]) ans += sz[idx] * (sz[idx] - 1) * (sz[idx] - 2);
else ans += sz[idx] * (sz[idx] - 1) * (sz[idx] - 2) / 3;
}
cout << ans << "\n";
return 0;
}
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