Submission #258703

#	Time	Username	Problem	Language	Result	Execution time	Memory
258703		dolphingarlic	Tram (CEOI13_tram)	C++14	0 / 100	1100 ms	1160 KiB

tram

#include <bits/stdc++.h>
typedef long long ll;
using namespace std;

int n, m;
bool used[150001][3];
pair<int, int> pos[30001];
set<int> hmmst;

int main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cin >> n >> m;
    hmmst.insert(1);
    hmmst.insert(n);
    for (int i = 1; i <= m; i++) {
        char c;
        cin >> c;
        if (c == 'E') {
            ll best_dist = 0;
            pair<int, int> best_pos;
            for (auto it = next(hmmst.begin()); it != hmmst.end(); it++) {
                int mid1 = (*it + *prev(it)) / 2,
                    mid2 = (*it + *prev(it) + 1) / 2;
                vector<pair<int, int>> cand = {
                    {*prev(it), 1}, {*prev(it), 2}, {mid1, 1}, {mid1, 2},
                    {mid2, 1},      {mid2, 2},      {*it, 1},  {*it, 2}};
                for (pair<int, int> j : cand) {
                    if (!used[j.first][j.second]) {
                        double d = 1e18;
                        bool available = false;
                        for (pair<int, int> k : cand) {
                            if (used[k.first][k.second]) {
                                available = true;
                                d = min(d, hypot(k.first - j.first, k.second - j.second));
                            }
                        }
                        if (d > best_dist && (available || hmmst.size() == 2)) {
                            best_dist = d;
                            best_pos = j;
                        }
                    }
                }
            }
            pos[i] = best_pos;
            used[pos[i].first][pos[i].second] = true;
            hmmst.insert(pos[i].first);
            cout << pos[i].first << ' ' << pos[i].second << '\n';
        } else {
            int idx;
            cin >> idx;
            used[pos[idx].first][pos[idx].second] = false;
            if (pos[idx].first != 1 && pos[idx].first != n &&
                !(used[pos[idx].first][0] || used[pos[idx].first][1]))
                hmmst.erase(pos[idx].first);
        }
    }
    return 0;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 15
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 15
• Subtask 8: 0 / 20