이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 200005;
const int INF = 1e9;
int N;
int A[MAXN];
map<int, int> dp[MAXN];
// dp[n][x] = minimum sequence in subtree of n if the root's value is x
// we only keep track of where min(cur, lc, rc)'s value end up in the dp
int Dp(int n, int x, int trace) {
if (n > N) return INF;
if (!trace && dp[n].count(x)) return dp[n][x];
if (trace) Dp(n, x, 0);
auto Trace = [&](int tid) {
if (!trace) return;
if (n * 2 + 0 <= N && tid & 1) swap(A[n], A[n * 2 + 0]);
if (n * 2 + 1 <= N && tid & 2) swap(A[n], A[n * 2 + 1]);
if (n * 2 + 0 <= N) Dp(n * 2 + 0, A[n * 2 + 0], 1);
if (n * 2 + 1 <= N) Dp(n * 2 + 1, A[n * 2 + 1], 1);
};
vector<int> a(3);
a[0] = x;
a[1] = (n * 2 + 0 <= N ? A[n * 2 + 0] : INF);
a[2] = (n * 2 + 1 <= N ? A[n * 2 + 1] : INF);
if (a[0] < min(a[1], a[2])) {
Trace(0);
return dp[n][x] = n;
}
if (a[1] < min(a[0], a[2])) {
Trace(1);
return dp[n][x] = Dp(n * 2, a[0], 0);
}
if (a[2] < min(a[0], a[1])) {
int xl = Dp(n * 2 + 0, a[0], 0);
int xr = Dp(n * 2 + 1, a[0], 0);
int yl = Dp(n * 2 + 0, a[1], 0);
int yr = Dp(n * 2 + 1, a[1], 0);
if (min(xl, yr) < min(xr, yl)) {
Trace(3);
return dp[n][x] = xl;
}
if (min(xl, yr) > min(xr, yl)) {
Trace(2);
return dp[n][x] = xr;
}
if (a[0] < a[1]) {
if (xl < xr) {
Trace(3);
return dp[n][x] = xl;
} else {
Trace(2);
return dp[n][x] = xr;
}
} else {
if (yr < yl) {
Trace(3);
return dp[n][x] = xl;
} else {
Trace(2);
return dp[n][x] = xr;
}
}
}
return -1;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0), cout.tie(0);
cin >> N;
for (int i = 1; i <= N; i++) {
cin >> A[i];
}
Dp(1, A[1], 1);
for (int i = 1; i <= N; i++) {
if (i > 1) {
cout << " ";
}
cout << A[i];
}
cout << "\n";
return 0;
}
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