Submission #256802

#	Time	Username	Problem	Language	Result	Execution time	Memory
256802		Pankin	Strah (COCI18_strah)	C++14	110 / 110	172 ms	40056 KiB

strah

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

/*
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("-O3")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
*/

#define mp make_pair
#define ll long long
#define ld long double
#define pb push_back
#define fast_io ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define fs first
#define sc second
#define getfiles ifstream cin("input.txt"); ofstream cout("output.txt");
#define endl '\n'
#define pii pair<ll, ll>

const ll INF = 2000000005;
const ll BIG_INF = 2000000000000000005;
const ll mod = 1000000007;
const ll P = 31;
const ld PI = 3.141592653589793238462643;
const double eps = 1e-9;

using namespace std;
using namespace __gnu_pbds;

bool valid(ll x, ll y, ll n, ll m) {
    return x >= 0 && y >= 0 && x < n && y < m;
}

mt19937 rng(1999999973);

typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> ordered_set;

const ll N = 2005;

ll n, m, nxt_r[N][N], ans = 0;
string s[N];

struct seg {
    ll l, r, mn;
    seg(ll l, ll r, ll mn) {
        this->l = l;
        this->r = r;
        this->mn = mn;
    }
    seg() {
        l = -1, r = -1, mn = 0;
    }
};

inline ll ariphm(ll l, ll r) {
    if (l > r)
        return 0;
    return (l + r) * (r - l + 1) / 2;
}

signed main() {
    fast_io;

    cin >> n >> m;
    for (ll i = 0; i < n; i++)
        cin >> s[i];
    for (ll i = 0; i < n; i++) {
        nxt_r[i][m - 1] = s[i][m - 1] != '#';
        for (ll j = m - 2; j >= 0; j--) {
            nxt_r[i][j] = nxt_r[i][j + 1] + 1;
            if (s[i][j] == '#')
                nxt_r[i][j] = 0;
        }
    }

    for (ll j = 0; j < m; j++) {
        vector<seg> st(1, seg());

        ll sum1 = 0, sum2 = 0;


        for (ll i = 0; i < n; i++) {
            while(st.back().mn > nxt_r[i][j]) {
                sum1 -= ariphm(st.back().l, st.back().r) * ariphm(1, st.back().mn);
                sum2 -= ariphm(1, st.back().mn) * (st.back().r - st.back().l + 1);
                st.pop_back();
            }
            st.pb(seg(st.back().r + 1, i, nxt_r[i][j]));
            sum1 += ariphm(st.back().l, st.back().r) * ariphm(1, st.back().mn);
            sum2 += ariphm(1, st.back().mn) * (st.back().r - st.back().l + 1);

            ans += sum2 * (i + 1) - sum1;
        }
    }

    cout << ans;


    return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 11 / 11
• Subtask 5: 11 / 11
• Subtask 6: 11 / 11
• Subtask 7: 11 / 11
• Subtask 8: 11 / 11
• Subtask 9: 11 / 11
• Subtask 10: 11 / 11