제출 #254853

#제출 시각UTC-0아이디문제언어결과실행 시간메모리
2548532020-07-30 18:04:10maximath_1Gap (APIO16_gap)C++11
100 / 100
72 ms1960 KiB
/*
* APIO 2016 Gap
* T = 1
> Two pointers, left right approaching the center
* T = 2
> pigeon hole principle
> get minimum and maximum,
> then divide the array into n - 1 approx. equal parts
> By PHP, one of these parts will be empty
> Thus, maximum gap >= the length of a part
> Now we can simply compare with seg[i].left - seg[i - 1].right
*/
#include "gap.h"
#include <iostream>
using namespace std;
#define ll long long
const ll mn = 0ll, mx = 1e18;
ll res = mn, arr[100005];
ll findGap(int t, int n){
if(t == 1){
ll lf = mn, rg = mx, k = 0;
for(int i = n; i > 0; i -= 2){
MinMax(lf, rg, &arr[k], &arr[n - 1 - k]);
lf = arr[k] + 1;
rg = arr[n - 1 - k] - 1;
 
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