Submission #254357

#	Time	Username	Problem	Language	Result	Execution time	Memory
254357		mode149256	Aliens (IOI16_aliens)	C++14	41 / 100	2081 ms	3956 KiB

aliens

/*input

*/
#include <bits/stdc++.h>
#include "aliens.h"
using namespace std;

namespace my_template {
typedef long long ll;
typedef long double ld;
typedef complex<ld> cd;

typedef pair<int, int> pi;
typedef pair<ll, ll> pl;
typedef pair<ld, ld> pd;

typedef vector<int> vi;
typedef vector<vi> vii;
typedef vector<ld> vd;
typedef vector<ll> vl;
typedef vector<vl> vll;
typedef vector<pi> vpi;
typedef vector<vpi> vpii;
typedef vector<pl> vpl;
typedef vector<cd> vcd;
typedef vector<pd> vpd;
typedef vector<bool> vb;
typedef vector<vb> vbb;
typedef std::string str;
typedef std::vector<str> vs;

#define x first
#define y second
#define debug(...) cout<<"["<<#__VA_ARGS__<<": "<<__VA_ARGS__<<"]\n"

const ld PI = 3.14159265358979323846264338327950288419716939937510582097494L;

template<typename T>
pair<T, T> operator+(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x + b.x, a.y + b.y); }
template<typename T>
pair<T, T> operator-(const pair<T, T> &a, const pair<T, T> &b) { return pair<T, T>(a.x - b.x, a.y - b.y); }
template<typename T>
T operator*(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.x + a.y * b.y); }
template<typename T>
T operator^(const pair<T, T> &a, const pair<T, T> &b) { return (a.x * b.y - a.y * b.x); }

template<typename T>
void print(vector<T> vec, string name = "") {
	cout << name;
	for (auto u : vec)
		cout << u << ' ';
	cout << '\n';
}
}
using namespace my_template;

const int MOD = 1000000007;
const ll INF = 1e15;
const int MX = 100101;

int N, M, K;
vpl sk;

// ll eval(pl line, ll at) {
// 	return at * line.x + line.y;
// }

// bool bad(pl x, pl y, pl z) {
// 	return (ll)(x.y - y.y) * (z.x - x.x) >= (ll)(x.y - z.y) * (y.x - x.x);
// }

void daryk(vl &dp, vi &cnt, ll lambda) {
	dp = vl(N + 1, INF);
	cnt = vi(N + 1, 0);

	dp[0] = 0;
	for (int i = 1; i <= N; ++i)
	{
		for (int t = 0; t < i; ++t)
		{
			ll newVal = dp[t] + (sk[i].x - sk[t + 1].y + 1) * (sk[i].x - sk[t + 1].y + 1)
			            - max(sk[t].x - sk[t + 1].y + 1, 0ll) * max(sk[t].x - sk[t + 1].y + 1, 0ll) + lambda;
			if (newVal < dp[i]) {
				dp[i] = newVal;
				cnt[i] = cnt[t] + 1;
			}
		}
	}
	dp[N] = dp[N] - cnt[N] * lambda;
}

// y < x
void sanitize(vi &r, vi &c) {
	vpl temp;
	for (int i = 0; i < N; ++i)
	{
		if (r[i] > c[i]) swap(r[i], c[i]);

		temp.emplace_back(c[i], r[i]);
	}
	sort(temp.begin(), temp.end(), [](const pl & a, const pl & b) {
		return a.x < b.x or (a.x == b.x and a.y > b.y);
	});

	for (int i = 0; i < N; ++i)
	{
		while (sk.size() and sk.back().y >= temp[i].y) sk.pop_back();

		sk.push_back(temp[i]);
	}
	N = (int)sk.size();
	sk.insert(sk.begin(), { -1, -1});
	// for (auto u : sk) printf("%d %d\n", u.x, u.y);
}

ll take_photos(int n, int m, int k, vi r, vi c) {
	N = n; M = m; K = k;
	sanitize(r, c);
	ll l = 0;
	ll h = 1e14;
	vl dp;
	vi cnt;

	while (l < h) {
		ll mi = (l + h + 1) / 2;
		daryk(dp, cnt, mi);
		// printf("pries l = %lld, h = %lld, mi = %lld, cnt = %d, K = %lld\n", l, h, mi, cnt[N], K);
		if (cnt[N] >= K)
			l = mi;
		else
			h = mi - 1;
		// printf("po l = %lld, h = %lld, mi = %lld\n", l, h, mi);
	}

	// printf("senas l = %d\n", l);
	daryk(dp, cnt, l);

	pl V1 = {dp[N], cnt[N]};

	l++;
	daryk(dp, cnt, l);

	pl V2 = {dp[N], cnt[N]};

	// printf("V1 = %lld %lld, V2 = %lld %lld\n", V1.x, V1.y, V2.x, V2.y);
	if (V2.y == K or V1.y == V2.y) return V2.x;

	return V1.x + (K - V1.y) * (V2.x - V1.x) / (V2.y - V1.y);
}

• Subtask 1: 4 / 4
• Subtask 2: 12 / 12
• Subtask 3: 9 / 9
• Subtask 4: 16 / 16
• Subtask 5: 0 / 19
• Subtask 6: 0 / 40