제출 #254027

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
254027		Vimmer	Domino (COCI15_domino)	C++14	30 / 160	4098 ms	157048 KiB

domino

#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>

#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-O3")
#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")

#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define pf push_front
#define N 100050
#define M ll(1e9 + 7)
#define inf 1e9 + 1e9

using namespace std;
//using namespace __gnu_pbds;

typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef short int si;
typedef array <ll, 3> a3;
typedef array <ll, 5> a5;

//typedef tree <ll, null_type, less_equal<ll>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;

ll ans = 0;

int n, k, a[2001][2001], mk[2001][2001], mx;

vector <pair <int, pair <int, pair <int, int> > > > vr;

void dfs(int v, ll kol)
{
    if (v == k) {ans = max(ans, kol); return;}

    for (int i = 0; i < min(mx, sz(vr)); i++)
    {
        int x = vr[i].S.S.F, y = vr[i].S.S.S;

        ll nkol = kol;

        if (mk[x][y] == 0) nkol += a[x][y];

        if (vr[i].S.F == 0 && !mk[x - 1][y]) nkol += a[x - 1][y];

        if (vr[i].S.F == 1 && !mk[x][y - 1]) nkol += a[x][y - 1];

        mk[x][y]++;

        if (vr[i].S.F == 0) mk[x - 1][y]++; else mk[x][y - 1]++;

        dfs(v + 1, nkol);

        mk[x][y]--;

        if (vr[i].S.F == 0) mk[x - 1][y]--; else mk[x][y - 1]--;
    }
}
int main()
{
    //freopen("input.txt", "r", stdin); //freopen("output4.txt", "w", stdout);

    ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);

    cin >> n >> k;

    while (pow(mx, k) < 5 * 1e8) mx++;

    mx--;

    ll sum = 0;

    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++) {cin >> a[i][j]; sum += ll(a[i][j]);}

    for (int i = 0; i < n; i++)
        for (int j = 0; j < n; j++)
        {
            if (i != 0) vr.pb({a[i][j] + a[i - 1][j], {0, {i, j}}});

            if (j != 0) vr.pb({a[i][j] + a[i][j - 1], {1, {i, j}}});
        }

    sort(vr.begin(), vr.end());

    reverse(vr.begin(), vr.end());

    dfs(0, 0);

    cout << sum - ans << endl;
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 0 / 10
• Subtask 4: 10 / 10
• Subtask 5: 0 / 10
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• Subtask 16: 0 / 10