This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "friend.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
// Find out best sample
int subtask1(int n,int confidence[],int host[],int protocol[]){
vector<vector<int>> adjlist(n);
for (int i = 1; i<n; i++){
if (protocol[i]==0){
adjlist[host[i]].push_back(i);
adjlist[i].push_back(host[i]);
} else if (protocol[i]==1){
for (int x : adjlist[host[i]]){
adjlist[i].push_back(x);
adjlist[x].push_back(i);
}
} else {
for (int x : adjlist[host[i]]){
adjlist[i].push_back(x);
adjlist[x].push_back(i);
};
adjlist[host[i]].push_back(i);
adjlist[i].push_back(host[i]);
}
}
ll mx = 0;
for (int i = 0; i<(1<<n); i++){
//check if ok
bool works = true;
ll tot = 0;
for (int j = 0; j<n; j++){
if ((1<<j)&i){
tot+=confidence[j];
for (int k : adjlist[j]){
if ((1<<k)&i){
works=false;
break;
}
}
}
if (works==false){
break;
}
}
if (works==false){
continue;
}
mx=max(mx,tot);
}
return mx;
}
int subtask2(int n,int confidence[],int host[],int protocol[]){
int tot = 0;
for (int i = 0; i<n; i++){
tot+=confidence[i];
}
return tot;
}
int subtask3(int n,int confidence[],int host[],int protocol[]){
int mx = 0;
for (int i = 0; i<n; i++){
mx=max(mx,confidence[i]);
}
return mx;
}
int subtask4(int n,int confidence[],int host[],int protocol[]){
return 0;
}
int subtask5(int n,int confidence[],int host[],int protocol[]){
return 0;
}
int subtask6(int n,int confidence[],int host[],int protocol[]){
return 0;
}
int findSample(int n,int confidence[],int host[],int protocol[]){
if (n<=10){
return subtask1(n,confidence,host,protocol);
} else {
bool protocols[3]={0,0,0};
for (int i = 1; i<n; i++){
protocols[protocol[i]]=true;
}
if (protocols[0]==1&&protocols[1]==0&&protocols[2]==0){
return subtask2(n,confidence,host,protocol);
} else if (protocols[0]==0&&protocols[1]==1&&protocols[2]==0){
return subtask3(n,confidence,host,protocol);
} else if (protocols[0]==0&&protocols[1]==0&&protocols[2]==1){
return subtask4(n,confidence,host,protocol);
} else if (protocols[0]==1&&protocols[1]==1&&protocols[2]==0){
return subtask5(n,confidence,host,protocol);
} else {
return subtask6(n,confidence,host,protocol);
}
}
return 0;
}
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