# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
253361 | Vimmer | Topovi (COCI15_topovi) | C++14 | 2096 ms | 23632 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
//#include <ext/pb_ds/tree_policy.hpp>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("-O3")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("fast-math")
//#pragma GCC optimize("no-stack-protector")
#define F first
#define S second
#define sz(x) int(x.size())
#define pb push_back
#define pf push_front
#define N 10005
#define M ll(998244353)
#define inf 1e9 + 1e9
using namespace std;
//using namespace __gnu_pbds;
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef short int si;
typedef array <ll, 3> a3;
typedef array <ll, 4> a4;
//typedef tree <int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
ll ans;
map <pair <ll, ll>, ll> a;
unordered_map <ll, ll> valx, valy, row, col;
set <ll> se;
void de(ll t, bool ob)
{
if (ob) valx[row[t]]--; else valy[col[t]]--;
}
void ad(ll t, bool ob)
{
if (ob) valx[row[t]]++; else valy[col[t]]++;
}
int main()
{
//freopen("input.txt", "r", stdin); //freopen("output4.txt", "w", stdout);
ios_base::sync_with_stdio(0); istream::sync_with_stdio(0); cin.tie(0); cout.tie(0);
ll n, k, p;
cin >> n >> k >> p;
for (ll i = 0; i < k; i++)
{
ll x, y, val;
cin >> x >> y >> val;
row[x] ^= val;
col[y] ^= val;
a[{x, y}] = val;
}
valy[0] = valx[0] = n;
for (auto it : col) {valy[0]--; valy[it.S]++;}
for (auto it : row) {valx[0]--; valx[it.S]++;}
for (auto it : valx) ans += it.S * valy[it.S];
for (; p > 0; p--)
{
ll x1, x2, y1, y2;
cin >> x1 >> y1 >> x2 >> y2;
ll val = a[{x2, y2}] = a[{x1, y1}];
de(x1, 1); de(x2, 1); de(y1, 0); de(y2, 0);
row[x1] ^= val; col[y1] ^= val; row[x2] ^= val; col[y2] ^= val;
ad(x1, 1); ad(x2, 1); ad(y1, 0); ad(y2, 0);
ll ans = 0;
for (auto it : valx) ans += it.S * valy[it.F];
cout << n * n - ans << '\n';
}
}
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