제출 #252407

#제출 시각아이디문제언어결과실행 시간메모리
252407khangalStreet Lamps (APIO19_street_lamps)C++14
40 / 100
1147 ms133268 KiB
#include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; typedef long long ll; typedef double db; typedef vector<long long> vl; typedef pair<long long , long long > pl; const int N=1e6+1; #define po pop_back #define pb push_back #define mk make_pair #define lw lower_bound #define up upper_bound #define ff first #define ss second #define boost ios_base::sync_with_stdio(); cin.tie(0); cout.tie(0); #define MOD 1000000007 #define MAX 1e18 #define MIN -1e18 #define rep(i,a,b) for(ll i=a;i<=b;i++) #define per(i,a,b) for(ll i=b;i>=a;i--) #define con continue #define freopen freopen("input.txt", "r", stdin);freopen("output.txt", "w", stdout); #define PI 3.14159265358979323846264338327950288419716939937510582097494459230781640628 // typedef tree<ll , null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> indexed_set; // template< typename T> // using indexed_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; ll n,m,ans,mid,mn,mx,cnt,T,sum,h1,h2,e[1234567],b[1234567],c[1234567],d[1<<20],k,i,j,l,h,a[1234567],w,x,y,z; ll c1[123][123]; bool used[1234567],used1[1234567]; pl p[1234567]; string s,s1[1234567]; map<ll,ll> mp; map<pl,ll> mpl; vector<pl> vec,vec1,ansvec; vector<ll> v[1234567],v1[1234567]; vector<ll> vp[1234567]; set<ll> st; stack <ll> sta; int main(){ cin>>n>>m; cin>>s; rep(i,0,n-1)if(s[i]=='1')d[i]=0; if(n<=100&&m<=100){ rep(i,0,n-1)c1[0][i+1]=s[i]-'0'; rep(k,1,m){ string str; cin>>str; rep(i,1,n)c1[k][i]=c1[k-1][i]; if(str == "query"){ c[k]=1; cin>>x>>y; ans=0; rep(i,0,k-1){ ll res=1; rep(j,x,y-1){ if(c1[i][j]==0)res=0; } ans += res; } cout<<ans<<'\n'; } else{ cin>>x; if(c1[k][x]==1)c1[k][x]=0; else c1[k][x]=1; } }} else{ rep(k,1,m){ string str; cin>>str; if(str=="query"){ cin>>x>>y; x--; y--; if(s[x]=='1')c[x]+=(k - d[x]),d[x]=k; cout<<c[x]<<'\n'; } else{ cin>>x; x--; if(s[x]=='1'){ c[x] += (k - d[x]); s[x]='0'; } else s[x]='1',d[x]=k; } } } }
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