제출 #252307

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
252307		leaked	Mate (COCI18_mate)	C++14	100 / 100	1724 ms	14860 KiB

mate

#include<bits/stdc++.h>
using namespace std;
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
//
//    #pragma GCC optimize("unroll-loops")
//    #pragma GCC optimize("Ofast")
//    #pragma GCC optimize("-O3")
//    #pragma GCC optimize("no-stack-protector")
//    #pragma GCC optimize("fast-math")
//#define LOCAL
#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
#ifndef LOCAL
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
	*this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
#else
sim dor(const c&) { ris; }
#endif
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "
#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int>a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ll long long
typedef unsigned long long ull;
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define fast_io cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
#define all(x) x.begin(),x.end()
#define getfiles    ifstream cin("input.txt");ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (int)x.size()
#define endl "\n"
#define rall(x) x.rbegin(),x.rend()
#define len(a) (ll)a.size()
#define rep(x,l,r) for(ll x=l;x<r;x++)

//using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
const ld pi=3.14159265359;
ll inf = 1e18,mod1=1e9+7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) { return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod : sqr(binpow(a, b / 2, mod)) % mod) : 1; }
ll binmult(ll a, ll b, ll mod) { return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod : (2 * binmult(a, b / 2, mod)) % mod) : 0; }
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
const ll R=1e4;
const ll tx[4]={0,0,-1,1};
const ll ty[4]={-1,1,0,0};
const char rev_to[4]={'E','W','N','S'};
const int N=2e3+1;
const int M=1e9+7;
//typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> st;
auto rnd=bind(uniform_int_distribution<ll>(1,125),mt19937(time(0)));
void bad(){
    cout<<-1;
    exit(0);
}
string s;
vector<int> pos[26];
int prec[N][26][26];
int f[N],inv[N];
void init(){
    f[0]=1;for(int i=1;i<N;i++) f[i]=(f[i-1]*1ll*i)%M;
    inv[N-1]=binpow(f[N-1],M-2,M);for(int i=N-2;i>=0;i--) inv[i]=(inv[i+1]*1ll*(i+1))%M;
}
ll C(int n,int k){
    if(!k) return 1;
    return 1ll*f[n]*inv[k]%M*inv[n-k]%M;
}
int n,q;
signed main()
{
    fast_io;
    cin>>s;n=sz(s);
    for(int i=0;i<n;i++){
        pos[s[i]-'a'].p_b(i);
    }
    init();
    for(int le=2;le<=sz(s);le++){
        for(int ch1=0;ch1<26;ch1++){
            for(auto &z : pos[ch1]){
                if(z+2<le) continue;
                for(int ch2=0;ch2<26;ch2++){
                    int poss=upper_bound(all(pos[ch2]),z)-pos[ch2].begin();
                    if(poss==sz(pos[ch2])) continue;
                    prec[le][ch1][ch2]=( prec[le][ch1][ch2]+(1ll*C(z,le-2)*(sz(pos[ch2])-poss)%M))%M;
//                    debug()<<imie(C(z,le-2))<<imie(sz(pos[ch2])-poss);
                }
            }
        }
    }
    cin>>q;
    while(q--){
        int a; char b,c;
        cin>>a;cin>>b>>c;
        cout<<prec[a][b-'a'][c-'a']<<endl;
    }
    return 0;
}
/*
0 0 0
2 1 3
3 2 7
1 3 8
1 4 2
3 5 3

/
*/

• Subtask 1: 100 / 100