oj.uz

답안 #252105

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
252105 2020-07-24T07:21:58 Z anonymous 조교 (CEOI16_popeala) C++14
26 / 100
 2000 ms 9100 KB 
#include <iostream>
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#pragma GCC optimize("unroll-loops")
#define MAXT 20005
#define MAXN 55
#define LL long long
#define INF (2100000000)
using namespace std;
int N, S, T, PT[MAXT];
char AC[MAXT][MAXN];
int Sum[MAXT], lo[MAXN], hi[MAXN], freq[MAXT];
int dp[MAXT][MAXN];
class Deque { //only sheet trust STL
    int DQ[MAXT];
    int l=0, r = 0; //[l,r) used
public:
    void nuke() {l = r = 0;}
    void putfront(int x) {
        DQ[r++] = x;
    }
    void popfront() {r--;}
    void popback() {l++;}
    int Front() {
        return(DQ[r-1]);
    }
    int Back() {
        return(DQ[l]);
    }
    int Size() {return(r-l);}
} DQ[MAXN];

int popcount(LL x) {
    int a = (x >> 30), b = x & ((1<<30) - 1);
    return(__builtin_popcount(a) + __builtin_popcount(b));
}

class SparseTable {
    LL ST[MAXT][15];
    int lg[MAXT];
public:
    void init() {
        for (int i=2; i<=T+3; i++) {
            lg[i] = lg[i/2] + 1;
        }
        for (int i=1; i<=T; i++) {
            for (int j=1; j<=N; j++) {
                if (AC[i][j] == '0') {
                    ST[i][0] |= 1LL << j;
                }
            }
        }
        for (int i=1; i<=14; i++) {
            for (int j=0; j<=T; j++) {
                ST[j][i] = ST[j][i-1] | ST[j + (1 << (i-1))][i-1];
            }
        }
    }
    int Num(int l, int r) {
        int lvl = lg[r - l + 1];
        return(popcount(ST[l][lvl] | ST[r - (1 << lvl) + 1][lvl]));
    }
} ST;

void add(int q, int p, int j) {
    int vnew = dp[p][j-1] - Sum[p] * (N-q);
    while (DQ[q].Size()) {
        if (dp[DQ[q].Front()][j-1] - (N-q) * Sum[DQ[q].Front()] >= vnew) {DQ[q].popfront();}
        else {break;}
    }
    DQ[q].putfront(p);
}

int main() {
    //freopen("popeala.in","r",stdin);
    //freopen("popeala.out","w",stdout);
    scanf("%d %d %d",&N,&T,&S);
    for (int i=1; i<=T; i++) {
        scanf("%d",&PT[i]);
    }
    for (int i=1; i<=N; i++) {
        for (int j=1; j<=T; j++) {
            scanf("\n%c\n",&AC[j][i]);
        }
    }
    for (int i=1; i<=T; i++) {
        dp[i][0] = INF; //inf big enough ?
        Sum[i] = Sum[i-1] + PT[i];
    }
    ST.init();
    for (int i=1; i<=T; i++) {
        freq[i] = ST.Num(i,i);
    }
    for (int j=1; j<=S; j++) {
        for (int i=0; i<=N; i++) {
            DQ[i].nuke();
            lo[i] = 0, hi[i] = -1;
        }
        dp[0][j] = INF;

        for (int i=1; i<=T; i++) {
            hi[0]++;
            add(0, i-1, j);
            dp[i][j] = INF;
            for (int q=0; q <= N; q++) {
                while (lo[q] <= hi[q]) {
                    if (q < freq[i] || ST.Num(lo[q]+1, i) != q) {
                        if (DQ[q].Size() && DQ[q].Back() == lo[q]) {
                            DQ[q].popback();
                        }
                        add(q+1, lo[q], j);
                        lo[q]++;
                        hi[q+1]++;
                    } else {
                        break;
                    }
                }
                if (DQ[q].Size() && dp[DQ[q].Back()][j-1] - (N-q) * Sum[DQ[q].Back()] <= INF - (N-q) * Sum[i]) {
                    dp[i][j] = min(dp[i][j], dp[DQ[q].Back()][j-1] + (N-q) * (Sum[i] - Sum[DQ[q].Back()]));
                }
            }
        }
        printf("%d\n",dp[T][j]);
    }
}

Compilation message

popeala.cpp: In function 'int main()':
popeala.cpp:77:10: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d %d %d",&N,&T,&S);
     ~~~~~^~~~~~~~~~~~~~~~~~~~~
popeala.cpp:79:14: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         scanf("%d",&PT[i]);
         ~~~~~^~~~~~~~~~~~~
popeala.cpp:83:18: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
             scanf("\n%c\n",&AC[j][i]);
             ~~~~~^~~~~~~~~~~~~~~~~~~~

Subtask #1
8.0 / 8.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 640 KB Output is correct
2 Correct 1 ms 640 KB Output is correct

Subtask #2
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 53 ms 768 KB Output is correct
2 Correct 46 ms 768 KB Output is correct
3 Correct 50 ms 768 KB Output is correct

Subtask #3
9.0 / 9.0

# 결과 실행 시간 메모리 Grader output
1 Correct 222 ms 1540 KB Output is correct
2 Correct 323 ms 1944 KB Output is correct
3 Correct 438 ms 2424 KB Output is correct

Subtask #4
0 / 74.0

# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 640 KB Output is correct
2 Correct 1 ms 640 KB Output is correct
3 Correct 53 ms 768 KB Output is correct
4 Correct 46 ms 768 KB Output is correct
5 Correct 50 ms 768 KB Output is correct
6 Correct 222 ms 1540 KB Output is correct
7 Correct 323 ms 1944 KB Output is correct
8 Correct 438 ms 2424 KB Output is correct
9 Correct 628 ms 3320 KB Output is correct
10 Correct 902 ms 4344 KB Output is correct
11 Correct 1925 ms 8788 KB Output is correct
12 Correct 1904 ms 8784 KB Output is correct
13 Execution timed out 2009 ms 9100 KB Time limit exceeded
14 Halted 0 ms 0 KB -