답안 #251950

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
251950 2020-07-23T08:50:46 Z Vladikus004 Spirale (COCI18_spirale) C++14
72 / 80
1 ms 384 KB
#include <bits/stdc++.h>
#define inf 2e9
#define all(v) v.begin(), v.end()
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair <int, int> pii;

const int N = 51;
int n, m, k, x[N], y[N], t[N], d[N][N];

int get_dist(int X, int Y, int ind){
    if (X == x[ind] && Y == y[ind]) return 1;
    if (t[ind] == 0){
        if (abs(X - x[ind]) <= y[ind] - Y){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (ny != Y){
                nx--; ny--;
                now += add + 6;
                add += 8;
            }
            while (nx != X){
                nx++;
                now--;
            }
            return now;
        }else
        if (abs(Y - y[ind]) <= X - x[ind]){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (nx != X){
                nx++; ny--;
                now += add + 4;
                add += 8;
            }
            while (ny != Y){
                ny++;
                now--;
            }
            return now;
        }else
        if (abs(X - x[ind]) <= -(y[ind] - Y)){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (ny != Y){
                nx++; ny++;
                now += add + 2;
                add += 8;
            }
            while (nx != X){
                nx--;
                now--;
            }
            return now;
        }else{
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (nx != X){
                nx--; ny++;
                now += add;
                add += 8;
            }
            while (ny != Y){
                ny--;
                now--;
            }
            return now;
        }
    }else{
        if (abs(X - x[ind]) <= y[ind] - Y){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (ny != Y){
                nx++; ny--;
                now += add + 2;
                add += 8;
            }
            while (nx != X){
                nx--;
                now--;
            }
            return now;
        }else
        if (abs(Y - y[ind]) <= X - x[ind]){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (nx != X){
                nx++; ny++;
                now += add + 4;
                add += 8;
            }
            while (ny != Y){
                ny--;
                now--;
            }
            return now;
        }else
        if (abs(X - x[ind]) <= -(y[ind] - Y)){
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (ny != Y){
                nx--; ny++;
                now += add + 6;
                add += 8;
            }
            while (nx != X){
                nx++;
                now--;
            }
            return now;
        }else{
            int nx = x[ind], ny = y[ind], add = 2, now = 1;
            while (nx != X){
                nx--; ny--;
                now += add;
                add += 8;
            }
            while (ny != Y){
                ny++;
                now--;
            }
            return now;
        }
    }
    return 0;
}

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    #ifdef LOCAL
        freopen("input.txt", "r", stdin);
    #endif // LOCAL
    cin >> n >> m >> k;
    for (int i = 0; i < k; i++){
        cin >> x[i] >> y[i] >> t[i];
        x[i]--; y[i]--;
    }
    for (int i = 0; i < n; i++){
        for (int j = 0; j < m; j++){
            int mn = inf;
            for (int g = 0; g < k; g++){
                mn = min(mn, get_dist(i, j, g));
            }
            d[i][j] = mn;
        }
    }
    for (int i = 0; i < n; i++){
        for (int j = 0; j < m; j++){
            cout << d[i][j] << " ";
        }
        cout << "\n";
    }
}
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 384 KB Output is correct
2 Correct 0 ms 384 KB Output is correct
3 Correct 0 ms 384 KB Output is correct
4 Correct 0 ms 384 KB Output is correct
5 Correct 0 ms 384 KB Output is correct
6 Correct 1 ms 384 KB Output is correct
7 Correct 0 ms 384 KB Output is correct
8 Correct 0 ms 384 KB Output is correct
9 Incorrect 1 ms 384 KB Output isn't correct
10 Correct 1 ms 384 KB Output is correct