Submission #251857

#	Time	Username	Problem	Language	Result	Execution time	Memory
251857		leaked	Automobil (COCI17_automobil)	C++14	50 / 100	1100 ms	65540 KiB

automobil

#include<bits/stdc++.h>
using namespace std;
//#include<ext/pb_ds/assoc_container.hpp>
//#include<ext/pb_ds/tree_policy.hpp>
//
//    #pragma GCC optimize("unroll-loops")
//    #pragma GCC optimize("Ofast")
//    #pragma GCC optimize("-O3")
//    #pragma GCC optimize("no-stack-protector")
//    #pragma GCC optimize("fast-math")
//#define LOCAL
#define sim template < class c
#define ris return * this
#define dor > debug & operator <<
#define eni(x) sim > typename \
  enable_if<sizeof dud<c>(0) x 1, debug&>::type operator<<(c i) {
sim > struct rge { c b, e; };
sim > rge<c> range(c i, c j) { return rge<c>{i, j}; }
sim > auto dud(c* x) -> decltype(cerr << *x, 0);
sim > char dud(...);
struct debug {
#ifndef LOCAL
~debug() { cerr << endl; }
eni(!=) cerr << boolalpha << i; ris; }
eni(==) ris << range(begin(i), end(i)); }
sim, class b dor(pair < b, c > d) {
  ris << "(" << d.first << ", " << d.second << ")";
}
sim dor(rge<c> d) {
  *this << "[";
  for (auto it = d.b; it != d.e; ++it)
	*this << ", " + 2 * (it == d.b) << *it;
  ris << "]";
}
#else
sim dor(const c&) { ris; }
#endif
};
#define imie(...) " [" << #__VA_ARGS__ ": " << (__VA_ARGS__) << "] "
#define fi first
#define f first
#define se second
#define s second
#define vi_a vector<int>a;
#define p_b push_back
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ll long long
typedef unsigned long long ull;
////////////////////////////////???????????????CHECK THIS OUT???????????????//////////////////////////////
#define ld long double
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define fast_io cin.tie(0);cout.tie(0);ios_base::sync_with_stdio(0);
#define all(x) x.begin(),x.end()
#define getfiles    ifstream cin("input.txt");ofstream cout("output.txt");
#define pw(x) (1ll << x)
#define sz(x) (int)x.size()
#define endl "\n"
#define rall(x) x.rbegin(),x.rend()
#define len(a) (ll)a.size()
#define rep(x,l,r) for(ll x=l;x<r;x++)

//using namespace __gnu_pbds;
ld eps = (ld)1 / 1e6;
const ld pi=3.14159265359;
ll inf = 1e18,mod1=1e9+7;
ll sqr(ll a) { return a * a; }
ll qb(ll a) { return a * a * a; }
ll gcd(ll a, ll b) { return !a ? b : gcd(b % a, a); }
ll binpow(ll a, ll b, ll mod) { return b ? (b % 2 ? (a * (sqr(binpow(a, b / 2, mod)) % mod)) % mod : sqr(binpow(a, b / 2, mod)) % mod) : 1; }
ll binmult(ll a, ll b, ll mod) { return b ? (b % 2 ? (2 * binmult(a, b / 2, mod) + a) % mod : (2 * binmult(a, b / 2, mod)) % mod) : 0; }
/////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////
const ll R=1e4;
const ll tx[4]={0,0,-1,1};
const ll ty[4]={-1,1,0,0};
const char rev_to[4]={'E','W','N','S'};
const int N=1e6+1e5;
const int M=1e9+7;
//typedef tree<ll,null_type,less<ll>,rb_tree_tag,tree_order_statistics_node_update> st;
auto rnd=bind(uniform_int_distribution<ll>(1,1e18),mt19937(time(0)));
char c[N];ll a1[N],a2[N];
ll val[(int)5e3][(int)5e3];
signed main()
{
    fast_io;
    ll n,m,k;
    cin>>n>>m>>k;
    ll r=0;
    for(int i=0;i<n;i++){
        for(int j=0;j<m;j++){
            val[i][j]=i*m+j+1;
            r+=val[i][j];r%=M;
        }
    }
    ll ans=((1+n*m)%M*(n*m)%M);
    int po=binpow(2,M-2,M);
    ans=ans*po%M;
    for(int i=0;i<k;i++){
        cin>>c[i]>>a1[i]>>a2[i];
//        if(i>64) continue;
        if(c[i]=='R'){
            ll f=(1+(a1[i]-1)*m)%M;
            ll last=(f+m-1)%M;
            ll perv=(f+last)*m%M*po%M;
            ll total=1;
            set<pll>st;
            for(int j=0;j<i;j++){
                if(c[j]==c[i]){
                    if(a1[j]==a1[i]){
                        perv=perv*a2[j]%M;
                        total=(total*a2[j])%M;
                    }
                }else{
                    auto c=st.lower_bound({a1[j],(ll)0});
                    if(c!=st.end() && c->f==a1[j]){
                        ll prev=c->s;
                        ll nxt=(prev*a2[j])%M;
                        perv=(perv-prev+M)%M;
                        perv=(perv+nxt)%M;
                        st.erase(c);
                        st.insert({a1[j],nxt});
                    }else{
                        ll prev=(total)%M*(f+a1[j]-1)%M;
                        ll nxt=prev*a2[j]%M;
                        perv=(perv-prev+M)%M;
                        perv=(perv+nxt)%M;
                        st.insert({a1[j],nxt});
                    }
                }
            }
            for(int j=0;j<m;j++){
                r=(r-val[a1[i]-1][j]+M)%M;
                val[a1[i]-1][j]=(val[a1[i]-1][j]*a2[i])%M;
                r=(r+val[a1[i]-1][j])%M;
            }
            ans=(ans-perv+M)%M;
            ans=(ans+(perv*a2[i])%M)%M;
//            debug()<<imie(r)<<imie(ans);
        }else{
            ll f=(1+(a1[i]-1))%M;
            ll last=(f+(n-1)*m)%M;
            ll perv=(f+last)*n%M*po%M;
            ll total=1;
            set<pll>st;
            for(int j=0;j<i;j++){
                if(c[j]==c[i]){
                    if(a1[j]==a1[i]){
                        perv=perv*a2[j]%M;
                        total=(total*a2[j])%M;
                    }
                }else{
                    auto c=st.lower_bound({a1[j],(ll)0});
                    if(c!=st.end() && c->f==a1[j]){
                        ll prev=c->s;
                        ll nxt=(prev*a2[j])%M;
                        perv=(perv-prev+M)%M;
                        perv=(perv+nxt)%M;
                        st.erase(c);
                        st.insert({a1[j],nxt});
                    }else{
                        ll prev=(total)%M*(f+(a1[j]-1)*m)%M;
                        ll nxt=prev*a2[j]%M;
                        perv=(perv-prev+M)%M;
                        perv=(perv+nxt)%M;
                        st.insert({a1[j],nxt});
                    }
                }
            }
            for(int j=0;j<n;j++){
                r=(r-val[j][a1[i]-1]+M)%M;
                val[j][a1[i]-1]=(val[j][a1[i]-1]*a2[i])%M;
                r=(r+val[j][a1[i]-1])%M;
            }
            ans=(ans-perv+M)%M;
            ans=(ans+(perv*a2[i])%M)%M;
//            assert(r==ans);
        }
//        if(r==888160991) debug()<<imie(i);
    }
    cout<<r;
    return 0;
}
/*
1  0  3  4
5  0  7  8

/
*/

• Subtask 1: 50 / 100