답안 #251747

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
251747 2020-07-22T09:13:02 Z ne4eHbKa Relativnost (COCI15_relativnost) C++17
0 / 140
30 ms 2304 KB
//{ <defines>
#include <bits/stdc++.h>
using namespace std;

//#pragma comment(linker, "/stack:200000000")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
//#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,-O3")

#define fr(i, n) for(int i = 0; i < n; ++i)
#define fo(n) fr(i, n)

#define re return
#define ef else if
#define ifn(x) if(!(x))
#define _  << ' ' <<

#define ft first
#define sd second
#define ve vector
#define pb push_back
#define eb emplace_back

#define sz(x) int((x).size())
#define bnd(x) x.begin(), x.end()
#define clr(x, y) memset((x), (y), sizeof (x))

typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef ve<int> vi;

inline ll time() {re chrono :: system_clock().now().time_since_epoch().count();}
mt19937 rnd(time());
mt19937_64 RND(time());

template<typename t> inline void umin(t &a, t b) {a = min(a, b);}
template<typename t> inline void umax(t &a, t b) {a = max(a, b);}

int md = 998244353;

inline int m_add(int&a, int b) {a += b; if(a < 0) a += md; if(a >= md) a -= md; re a;}
inline int m_sum(int a, int b) {a += b; if(a < 0) a += md; if(a >= md) a -= md; re a;}
inline int m_mul(int&a, int b) {re a = 1ll * a * b % md;}
inline int m_prod(int a, int b) {re 1ll * a * b % md;}

int m_bpow(ll A, ll b) {
    int a = A % md;
    ll ans = 1;
    for(ll p = 1ll << 63 - __builtin_clzll(b); p; p >>= 1) {
        (ans *= ans) %= md;
        if(p & b)
            (ans *= a) %= md;
    }
    re ans;
}

//const ld pi = arg(complex<ld>(-1, 0));
//const ld pi2 = pi + pi;
const int oo = 2e9;
const ll OO = 4e18;
//} </defines>
const int N = 1e5 + 5;
const short smd = 1e4 + 7;

int n, c, q;
int a[N], b[N];

char MEM[16 * 1024 * 1024], *mptr;

inline void* getmem(size_t f) {
    void* res = mptr;
    mptr += f;
    return res;
}

struct tree {
    short *v;
    tree *l, *r;
    void merge(int ul, int ur, bool cl = false) {
        if(!cl) memset(v, 0, min(c, ul + ur) + 1 << 1);
        short *fi = l->v, *se;
        for(int i = 0, j; i <= min(ul, c); ++i, ++fi) {
            if(!*fi) continue;
            se = r->v;
            for(j = 0; j <= min(ur, c); ++j, ++se) {
                if(!*se) continue;
                short &t = v[min(c, i + j)];
                t += *fi * *se % md;
                if(t >= smd) t -= smd;
            }
        }
    }
    tree(int tl = 0, int tr = n - 1) {
        v = (short*) getmem(min(c + 1, tr - tl + 2) << 1);
        if(tl < tr) {
            int tm = tl + tr >> 1;
            l = new tree(tl, tm);
            r = new tree(tm + 1, tr);
            merge(tm - tl + 1, tr - tm, true);
        } else {
            v[0] = b[tl];
            v[1] = a[tl];
        }
    }
    void upd(int i, int tl = 0, int tr = n - 1) {
        if(tl == tr) {
            v[0] = b[tl];
            v[1] = a[tl];
            return;
        }
        int tm = tl + tr >> 1;
        i <= tm ? l->upd(i, tl, tm)
                : r->upd(i, tm + 1, tr);
        merge(tm - tl + 1, tr - tm);
    }
#ifdef _LOCAL
    ~tree() {
        free(v);
    }
#endif
};

void solve() {
    md = 1e4 + 7;
    cin >> n >> c;
    fo(n) cin >> a[i], a[i] %= md;
    fo(n) cin >> b[i], b[i] %= md;
    tree *t = new tree();
    cin >> q;
    while(q--) {
        int i, na, nb; cin >> i >> na >> nb;
        if(c > n) {
            cout << "0\n";
            continue;
        }
        na %= md, nb %= md, --i;
        a[i] = na, b[i] = nb;
        t->upd(i);
        cout << t->v[c] << '\n';
    }
}

int main() {
#ifdef _LOCAL
    freopen("in.txt", "r", stdin);
    int tests; cin >> tests;
    for(int test = 1; test <= tests; ++test) {
		cerr << "case #" << test << endl;
        solve();
        cerr << endl;
    }
#else
//    freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout);
    ios_base :: sync_with_stdio(0); cin.tie(0); cout.tie(0);
    solve();
#endif
    return 0;
}

Compilation message

relativnost.cpp: In function 'int m_bpow(ll, ll)':
relativnost.cpp:50:26: warning: suggest parentheses around '-' inside '<<' [-Wparentheses]
     for(ll p = 1ll << 63 - __builtin_clzll(b); p; p >>= 1) {
                       ~~~^~~~~~~~~~~~~~~~~~~~
relativnost.cpp: In member function 'void tree::merge(int, int, bool)':
relativnost.cpp:81:46: warning: suggest parentheses around '+' inside '<<' [-Wparentheses]
         if(!cl) memset(v, 0, min(c, ul + ur) + 1 << 1);
                              ~~~~~~~~~~~~~~~~^~~
relativnost.cpp: In constructor 'tree::tree(int, int)':
relativnost.cpp:97:25: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
             int tm = tl + tr >> 1;
                      ~~~^~~~
relativnost.cpp: In member function 'void tree::upd(int, int, int)':
relativnost.cpp:112:21: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
         int tm = tl + tr >> 1;
                  ~~~^~~~
# 결과 실행 시간 메모리 Grader output
1 Runtime error 2 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
2 Runtime error 2 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
3 Runtime error 2 ms 512 KB Execution killed with signal 11 (could be triggered by violating memory limits)
4 Runtime error 17 ms 1536 KB Execution killed with signal 11 (could be triggered by violating memory limits)
5 Runtime error 27 ms 2044 KB Execution killed with signal 11 (could be triggered by violating memory limits)
6 Runtime error 30 ms 2304 KB Execution killed with signal 11 (could be triggered by violating memory limits)
7 Runtime error 22 ms 1792 KB Execution killed with signal 11 (could be triggered by violating memory limits)
8 Runtime error 28 ms 2176 KB Execution killed with signal 11 (could be triggered by violating memory limits)
9 Runtime error 24 ms 1912 KB Execution killed with signal 11 (could be triggered by violating memory limits)
10 Runtime error 23 ms 1792 KB Execution killed with signal 11 (could be triggered by violating memory limits)