Submission #251395

#	Time	Username	Problem	Language	Result	Execution time	Memory
251395		Hasti	Nadan (COCI18_nadan)	C++17	50 / 50	1 ms	384 KiB

nadan

///A drunk man will find his way home, but a drunk bird may get lost forever...
#include <bits/stdc++.h>
#include<ext/pb_ds/assoc_container.hpp>
#include<ext/pb_ds/tree_policy.hpp> 
using namespace __gnu_pbds;
using namespace std;
//template <typename T>
//using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef tree<double, null_type, less_equal<double>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
#define int long long
typedef long long ll;
typedef double dd;
typedef long double ldd;
typedef pair <int, int> pii;
typedef pair <pii , int> ppii;
#define pb push_back
#define pf push_front
#define ppb pop_back()
#define ppf pop_front()
#define f first
#define s second
#define sz(x) (int)x.size()
#define smin(x , y) x = min(x , y)
#define smax(x , y) x = max(x , y)
#define mp make_pair
#define all(x) x.begin() , x.end()
#define debug(x) cerr<< #x << " = " << x << endl
#define ddebug(x, y) cerr<< #x << " = " << x  << ", " << #y << " = " << y << endl
#define uop(x, y) pii(min(x, y), max(x, y))
#define mem(a, b) memset(a, b, sizeof a)
#define sq(x) (x) * (x)
#define out return cout << "-1" << endl, 0
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops")
#pragma GCC optimize("no-stack-protector,fast-math,-ffp-contract=off")
//const int mx = 1e3 + 10;
int32_t main(){
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    cout.tie(0);
	int n, k;
	cin >> k >> n;
	k -= n * (n + 1) / 2;
	for(int i = 1; i < n; i++)
		cout << i << '\n';
	cout << n + k << '\n';
	return 0;
}

• Subtask 1: 50 / 50