Submission #250870

#	Time	Username	Problem	Language	Result	Execution time	Memory
250870		srvlt	Luxury burrow (IZhO13_burrow)	C++14	100 / 100	1223 ms	8440 KiB

burrow

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define ll long long
#define ld long double
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define SZ(x) (int)(x).size()
template <typename T> using ord_set = tree <T, null_type, less <T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const int n0 = 1003;
int n, m, k, a[n0][n0], dp[n0][n0], l[n0], r[n0];
vector <int> v;

int get(int x) {
	int res = 0;
	for (int j = 1; j <= m; j++) {
		for (int i = 1; i <= n; i++)
			dp[i][j] = (a[i][j] >= x) ? (dp[i][j - 1] + 1) : 0;
		v.clear();
		for (int i = 1; i <= n; i++) {
			while (!v.empty() && dp[v.back()][j] >= dp[i][j])
				v.pop_back();
			if (v.empty()) l[i] = 1;
			else l[i] = v.back() + 1;
			v.pb(i);
		}
		v.clear();
		for (int i = n; i >= 1; i--) {
			while (!v.empty() && dp[v.back()][j] >= dp[i][j])
				v.pop_back();
			if (v.empty()) r[i] = n;
			else r[i] = v.back() - 1;
			v.pb(i);
			res = max(res, (r[i] - l[i] + 1) * dp[i][j]);
		}
	}
	return res;
}

int main() {
	ios_base::sync_with_stdio(false), cin.tie(NULL);
	#ifdef LOCAL
		freopen("input.txt", "r", stdin);
	#endif
	
	cin >> n >> m >> k;
	for (int i = 1; i <= n; i++)
		for (int j = 1; j <= m; j++)
			cin >> a[i][j];
	int l = 1, r = (int)1e9 + 1;
	while (l < r - 1) {
		int mid = l + r >> 1;
		if (get(mid) >= k) l = mid;
		else r = mid;
	}
	cout << l << ' ' << get(l);
}

Compilation message (stderr)

burrow.cpp: In function 'int main()':
burrow.cpp:56:15: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
   int mid = l + r >> 1;
             ~~^~~

• Subtask 1: 100 / 100