제출 #250664

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
250664		Evirir	수열 (APIO14_sequence)	C++17	71 / 100	263 ms	131076 KiB

sequence

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

#define watch(x) cout<<(#x)<<"="<<(x)<<'\n'
#define mset(d,val) memset(d,val,sizeof(d))
#define setp(x) cout<<fixed<<setprecision(x)
#define forn(i,a,b) for(int i=(a);i<(b);i++)
#define fore(i,a,b) for(int i=(a);i<=(b);i++)
#define pb push_back
#define F first
#define S second
#define pqueue priority_queue
#define fbo find_by_order
#define ook order_of_key
typedef long long ll;
typedef pair<ll,ll> ii;
typedef vector<ll> vi;
typedef vector<ii> vii;
typedef long double ld;
typedef tree<ll, null_type, less<ll>, rb_tree_tag, tree_order_statistics_node_update> pbds;
void amin(ll &a, ll b){ a=min(a,b); }
void amax(ll &a, ll b){ a=max(a,b); }
void YES(){cout<<"YES\n";} void NO(){cout<<"NO\n";}
void SD(int t=0){ cout<<"PASSED "<<t<<endl; }
const ll INF = ll(1e18);
const int MOD = 998244353;

struct Line {
	ll m, b;
	Line(ll _m, ll _b) : m(_m), b(_b) {}
	inline ll eval(ll x) { return m * x + b; }
};

struct ConvexHull {
	deque<Line> d;
	inline void clear() { d.clear(); }
	bool irrelevant(Line Z) {
		if(int(d.size()) < 2) return false;
		Line X = d[int(d.size())-2], Y = d[int(d.size())-1];
		return (X.b - Z.b) * (Y.m - X.m) <= (X.b - Y.b) * (Z.m - X.m);
	}
	void addline(ll m, ll b) {
		Line l = Line(m,b);
		while(irrelevant(l)) d.pop_back();
		d.push_back(l);
	}
	Line query(ll x) {
		if(d.empty()) return Line{0,0};
		while(int(d.size()) > 1 && (d[0].b - d[1].b <= x * (d[1].m - d[0].m))) d.pop_front();
		return d.front();
	}
};

const bool DEBUG = 0;
const int MAXN = 100005;
const int MAXK = 205;

int n,K;
ll s[MAXN], dp[MAXK][MAXN], nxt[MAXK][MAXN];

int main()
{
	ios_base::sync_with_stdio(0); cin.tie(0);
	
	cin>>n>>K;
	forn(i,0,n){
		cin>>s[i];
		if(i>0) s[i]+=s[i-1];
	}
	
	ConvexHull cht;
	
	fore(i,1,K)
	{
		cht.clear();
		forn(j,0,n)
		{
			Line res = cht.query(s[j]);
			nxt[i][j] = res.m;
			dp[i][j] = res.eval(s[j]);
			cht.addline(s[j], dp[i-1][j]-s[j]*s[j]);
		}
	}
	
	vi ans;
	int cur=n-1;
	for(int i=K;i>=1;i--){
		for(int j=cur-1;j>=0;j--){
			if(s[j]==nxt[i][cur]){
				ans.pb(j);
				cur=j;
				break;
			}
		}
	}
	
	cout<<dp[K][n-1]<<'\n';
	for(ll x: ans) cout<<x+1<<" ";
	cout<<'\n';
	
	return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 21 / 21
• Subtask 6: 0 / 29