이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "minerals.h"
#include <bits/stdc++.h>
#define TRACE(x) std::cerr << #x << " :: " << x << std::endl
#define _ << " " <<
#define SZ(x) (int)(x).size()
#define ALL(x) (x).begin(),(x).end()
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
#define RFOR(i,a,b) for (int i=(a);i>=(b);--i)
const int mxN = 43005;
int inside[2*mxN];
int curVal, curAns;
int Add(int i) {
if (!inside[i]) {
inside[i] = true;
curVal = Query(i);
}
return curVal;
}
int Del(int i) {
if (inside[i]) {
inside[i] = false;
curVal = Query(i);
}
return curVal;
}
void Ans(int a, int b) { Answer(a,b); ++curAns; }
void rec(std::vector<int>& a, std::vector<int>& b) {
//~ for (int x : a) std::cout << x << ' ';
//~ std::cout << "| ";
//~ for (int x : b) std::cout << x << ' ';
//~ std::cout << std::endl;
if (SZ(a) == 1) { Ans(a[0],b[0]); return; }
int m = (SZ(a)-1)/2;
std::vector<int> ax, ay, bx, by;
FOR(i,0,m){
ax.push_back(a[i]);
Add(a[i]);
}
FOR(i,m+1,SZ(a)-1){
ay.push_back(a[i]);
Del(a[i]);
}
for (int& e : b) {
int r = curVal;
if (SZ(by) == SZ(ay) || (inside[e] ? Del(e) : Add(e)) == r) bx.push_back(e);
else by.push_back(e);
}
rec(ax,bx);
rec(ay,by);
}
void Solve(int N) {
std::vector<int> a, b;
int r = 0;
FOR(i,1,2*N){
int s = Add(i);
if (s > r) a.push_back(i), r = s;
else b.push_back(i);
}
rec(a,b);
}
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