이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "simurgh.h"
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define ll long long
#define ld long double
#define pb push_back
#define all(x) (x).begin(), (x).end()
#define SZ(x) (int)(x).size()
template <typename T> using ord_set = tree <T, null_type, less <T>, rb_tree_tag, tree_order_statistics_node_update>;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int n0 = 243, m0 = 29000;
int N, M, used[n0], ch[m0], par[n0], sp[m0], same[m0];
int in[n0], out[n0], T, common;
vector <int> g[n0], V, U, query;
void dfs(int v) {
used[v] = 1;
in[v] = ++T;
for (int i : g[v]) {
int to = V[i] ^ U[i] ^ v;
if (used[to]) continue;
par[to] = i;
query.pb(i);
sp[i] = 1;
dfs(to);
}
out[v] = T;
}
bool upper(int v, int u) {
return in[v] <= in[u] && out[u] <= out[v];
}
void add(int x) {
query.pb(x);
}
void del(int x) {
for (int i = 0; i < SZ(query); i++) {
if (query[i] == x) {
query.erase(query.begin() + i);
break;
}
}
}
std::vector<int> find_roads(int n, std::vector<int> u, std::vector<int> v) {
memset(& ch, -1, sizeof(ch));
N = n, M = u.size(), V = v, U = u;
for (int i = 0; i < M; i++)
g[v[i]].pb(i), g[u[i]].pb(i);
dfs(0);
vector <int> path;
common = count_common_roads(query);
for (int i = 0; i < M; i++) {
if (sp[i]) continue;
int a = v[i], b = u[i];
if (upper(b, a)) swap(a, b);
assert(upper(a, b));
path.clear();
while (b != a) {
path.pb(par[b]);
b = v[par[b]] ^ u[par[b]] ^ b;
}
add(i);
for (int j : path) {
if (ch[i] != -1 && ch[j] != -1) continue;
del(j);
int x = count_common_roads(query);
if (x == common) {
if (ch[j] != -1) ch[i] = ch[j];
same[j] = 1;
} else {
if (x == common - 1) {
ch[i] = 0;
ch[j] = 1;
}
if (x == common + 1) {
ch[i] = 1;
ch[j] = 0;
}
}
add(j);
}
if (ch[i] == -1) ch[i] = 0;
del(i);
for (int j : path) {
if (same[j]) ch[j] = ch[i];
same[j] = 0;
}
}
vector <int> res;
for (int i = 0; i < M; i++) {
if (ch[i] == -1) ch[i] = 1;
if (ch[i] == 1) res.pb(i);
}
return res;
}
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