이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define pb push_back
#define dbg(x) cerr << #x << " " << x << "\n"
const int N = 2e5, LG = 20;
int p[LG][1 + N];
int d[1 + N], a[1 + N];
vector <int> gr[1 + N];
int n, m, q;
void dfs (int node, int par) {
d[node] = d[par] + 1;
p[0][node] = par;
for (int son : gr[node])
if (par != son)
dfs (son, node);
}
void lift () {
for (int k = 1; k < LG; k++)
for (int node = 1; node <= n; node++)
p[k][node] = p[k - 1][p[k - 1][node]];
}
int lca (int a, int b) {
int k;
k = LG - 1;
while (d[a] > d[b]) {
if (d[p[k][a]] >= d[b])
a = p[k][a];
k--;
}
k = LG - 1;
while (d[a] < d[b]) {
if (d[p[k][b]] >= d[a])
b = p[k][b];
k--;
}
k = LG - 1;
while (k >= 0) {
if (p[k][a] != p[k][b])
a = p[k][a], b = p[k][b];
k--;
}
if (a != b)
a = p[0][a];
return a;
}
multiset <int> simple[1 + N];
multiset <int> two[1 + N];
int main () {
ios::sync_with_stdio (false);
cin.tie (0); cout.tie (0);
cin >> n >> m >> q;
for (int i = 1; i < n; i++) {
int x, y;
cin >> x >> y;
gr[x].pb (y);
gr[y].pb (x);
}
dfs (1, 0);
lift ();
for (int i = 1; i <= m; i++) {
cin >> a[i];
simple[a[i]].insert (i);
}
for (int i = 1; i < m; i++)
two[lca (a[i], a[i + 1])].insert (i);
while (q--) {
int type;
cin >> type;
if (type == 1) {
int pos, value;
cin >> pos >> value;
simple[a[pos]].erase (pos);
if (pos > 1)
two[lca (a[pos], a[pos - 1])].erase (pos - 1);
if (pos < m)
two[lca (a[pos], a[pos + 1])].erase (pos);
a[pos] = value;
simple[a[pos]].insert (pos);
if (pos > 1)
two[lca (a[pos], a[pos - 1])].insert (pos - 1);
if (pos < m)
two[lca (a[pos], a[pos + 1])].insert (pos);
}
else {
int l, r, value;
cin >> l >> r >> value;
auto it = simple[value].lower_bound (l);
if (it != simple[value].end () && *it <= r)
cout << *it << " " << *it << "\n";
else {
it = two[value].lower_bound (l);
if (it != two[value].end () && *it < r)
cout << *it << " " << *it + 1 << "\n";
else
cout << "-1 -1\n";
}
}
}
return 0;
}
/**
5 4 4
1 2
3 1
3 4
5 3
4 5 2 3
2 1 3 1
1 3 5
2 3 4 5
2 1 3 1
**/
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