이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <algorithm>
#include <assert.h>
#include <bitset>
#include <cmath>
#include <complex>
#include <deque>
#include <functional>
#include <iostream>
#include <limits.h>
#include <map>
#include <math.h>
#include <queue>
#include <set>
#include <stdlib.h>
#include <string.h>
#include <string>
#include <time.h>
#include <unordered_map>
#include <unordered_set>
#include <vector>
#pragma warning(disable:4996)
#pragma comment(linker, "/STACK:336777216")
using namespace std;
#define mp make_pair
#define Fi first
#define Se second
#define pb(x) push_back(x)
#define szz(x) ((int)(x).size())
#define rep(i, n) for(int i=0;i<n;i++)
#define all(x) (x).begin(), (x).end()
#define ldb ldouble
typedef tuple<int, int, int> t3;
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ldb;
typedef pair <int, int> pii;
typedef pair <ll, ll> pll;
typedef pair <ll, int> pli;
typedef pair <db, db> pdd;
int IT_MAX = 1 << 19;
const ll MOD = 1000000007;
const int INF = 0x3f3f3f3f;
const ll LL_INF = 0x3f3f3f3f3f3f3f3f;
const db PI = acos(-1);
const db ERR = 1e-10;
int in[300050];
int in2[300050];
int L[300050];
int R[300050];
ll sum1[300050];
ll sum2[300050];
class Node {
public:
ll s1, s2;
bool chk;
Node() {
*this = Node(0, 0, false);
}
Node(ll s1, ll s2, bool chk) : s1(s1), s2(s2), chk(chk) {}
};
Node operator + (Node a, Node b) {
swap(a, b);
Node rv;
if (!a.chk) {
rv.s1 = a.s1 + b.s1;
rv.s2 = a.s2 + b.s2;
rv.chk = b.chk;
}
else {
rv.s1 = a.s1 + b.s2;
rv.s2 = a.s2 + b.s1;
rv.chk = !b.chk;
}
return rv;
}
vector <pii> V1;
vector <pii> V2;
vector <pii> Vx;
Node val[600050];
int ch(pii x) {
int st = 0, en = (int)Vx.size() - 1, mi, rv = 0;
while (st <= en) {
mi = (st + en) / 2;
if (mp(in2[Vx[mi].first], Vx[mi]) <= mp(in2[x.first], x)) {
rv = mi;
st = mi + 1;
}
else en = mi - 1;
}
return rv;
}
Node indt[2100000];
void update(int p, Node v) {
p += IT_MAX;
indt[p] = v;
for (p /= 2; p; p /= 2) indt[p] = indt[2 * p] + indt[2 * p + 1];
}
int ans[300050];
int main() {
int N, i;
scanf("%d", &N);
for (i = 0; i < N; i++) scanf("%d", &in[i]);
int mnp = 0;
for (i = 1; i < N; i++) if (in[mnp] > in[i]) mnp = i;
for (i = 1; i < N; i++) in2[i] = in[(mnp + i) % N];
vector <pii> Vu;
for (i = 1; i < N; i++) {
while (!Vu.empty()) {
if (Vu.back().first < in2[i]) break;
Vu.pop_back();
}
if (!Vu.empty()) L[i] = Vu.back().second;
else L[i] = 0;
Vu.emplace_back(in2[i], i);
}
Vu.clear();
for (i = N - 1; i >= 1; i--) {
while (!Vu.empty()) {
if (Vu.back().first < in2[i]) break;
Vu.pop_back();
}
if (!Vu.empty()) R[i] = Vu.back().second;
else R[i] = N;
Vu.emplace_back(in2[i], i);
}
for (i = 1; i < N; i++) {
while (!V1.empty()) {
int t = V1.back().first;
if (in2[t] < in2[i]) break;
V1.pop_back();
}
int st = 1;
if (!V1.empty()) st = V1.back().first + 1;
Vx.emplace_back(i, st);
V1.emplace_back(i, st);
}
for (i = N - 1; i >= 1; i--) {
while (!V2.empty()) {
int t = V2.back().first;
if (in2[t] < in2[i]) break;
V2.pop_back();
}
int en = N - 1;
if (!V2.empty()) en = V2.back().first - 1;
Vx.emplace_back(i, en);
V2.emplace_back(i, en);
}
sort(all(Vx), [](pii a, pii b) {
if(in2[a.first] != in2[b.first]) return in2[a.first] < in2[b.first];
else return a < b;
});
Vx.erase(unique(all(Vx)), Vx.end());
for (i = 1; i < N; i++) {
sum1[i] = sum1[i - 1] + in2[i];
sum2[i] = (i == 1 ? 0 : sum2[i - 2]) + in2[i];
}
for (i = 0; i < Vx.size(); i++) {
pii u = Vx[i];
if (u.first >= u.second) {
val[i].s1 = sum2[u.first];
if (u.second % 2 == u.first % 2) {
if (u.second != 1) val[i].s1 -= sum2[u.second - 2];
}
else val[i].s1 -= sum2[u.second - 1];
val[i].s2 = (sum1[u.first] - sum1[u.second - 1]) - val[i].s1;
}
else {
val[i].s2 = sum2[u.second];
if (u.second % 2 == u.first % 2) {
if (u.first != 1) val[i].s2 -= sum2[u.first - 2];
}
else val[i].s2 -= sum2[u.first - 1];
val[i].s1 = (sum1[u.second] - sum1[u.first - 1]) - val[i].s2;
}
val[i].chk = (u.first % 2 == u.second % 2);
}
IT_MAX = 1 << 20;
V1.clear();
for (auto it : V2) {
// printf("%d\n", ch(it));
update(ch(it), val[ch(it)]);
}
for (i = 1; i < N; i++) {
pii u = V2.back();
V2.pop_back();
update(ch(u), Node());
int st = i + 1, en = u.second;
vector <pii> Vu2;
while (st <= en) {
pii u2 = pii(st, R[st] - 1);
update(ch(u2), val[ch(u2)]);
Vu2.push_back(u2);
st = R[st];
}
reverse(all(Vu2));
for (auto it : Vu2) V2.emplace_back(it);
ans[(mnp + i) % N] = indt[1].s2 + in2[i];
while (!V1.empty()) {
int t = V1.back().first;
if (in2[t] < in2[i]) break;
update(ch(V1.back()), Node());
V1.pop_back();
}
st = 1;
if (!V1.empty()) st = V1.back().first + 1;
V1.emplace_back(i, st);
update(ch(V1.back()), val[ch(V1.back())]);
}
if (N % 2 == 1) {
for (i = 0; i < N; i++) ans[i] += in[mnp];
}
int st = 1, en = N - 1;
ans[mnp] = in[mnp];
for(i = 1; i < N; i++) {
if (in2[st] > in2[en]) {
if (i % 2 == 0) ans[mnp] += in2[st];
st++;
}
else {
if (i % 2 == 0) ans[mnp] += in2[en];
en--;
}
}
for (i = 0; i < N; i++) printf("%d\n", ans[i]);
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
cake.cpp:23:0: warning: ignoring #pragma warning [-Wunknown-pragmas]
#pragma warning(disable:4996)
^
cake.cpp:24:0: warning: ignoring #pragma comment [-Wunknown-pragmas]
#pragma comment(linker, "/STACK:336777216")
^
cake.cpp: In function 'int main()':
cake.cpp:174:16: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i = 0; i < Vx.size(); i++) {
^
cake.cpp:113:17: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf("%d", &N);
^
cake.cpp:114:45: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
for (i = 0; i < N; i++) scanf("%d", &in[i]);
^
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