제출 #248559

#제출 시각아이디문제언어결과실행 시간메모리
248559wzy회문 (APIO14_palindrome)C++11
73 / 100
44 ms31508 KiB
#include <iostream> #include <iomanip> #include <cstdio> #include <cstdlib> #include <algorithm> #include <cmath> #include <vector> #include <set> #include <map> #include <unordered_set> #include <unordered_map> #include <queue> #include <ctime> #include <cassert> #include <complex> #include <string> #include <cstring> #include <chrono> #include <random> #include <bitset> #include <climits> using namespace std; #define F first #define S second #define rep(i, a, b) for(int i = a; i < (b); ++i) #define per(i, a, b) for(int i = b-1; i>=a ; i--) #define trav(a, x) for(auto& a : x) #define allin(a , x) for(auto a : x) #define all(x) begin(x) , end(x) #define sz(x) (int)(x).size() #define pb push_back typedef long long ll; typedef pair<int, int> pii; typedef vector<ll> vl; typedef vector<pii> vpi; typedef pair<ll,ll> pll; typedef vector<string> vs; typedef vector<pll> vpl; typedef vector<int> vi; ll modpow(ll b, ll e ,ll mod){ ll ans = 1; for (; e; b = b * b % mod, e /= 2) if (e & 1) ans = ans * b % mod; return ans; } const int N = 100005; string s; int bigsuf = -1 , id = 2; struct node{ int link , len , occ; vi go; } tree[N]; void init(){ bigsuf = 2; id = 2; tree[1].len = -1 , tree[1].link = 1, tree[1].go = vi(26,0) , tree[1].occ = 0; tree[2].len = 0 , tree[2].link = 1 , tree[2].go = vi(26,0) , tree[2].occ = 0; } void append(int p){ int cur = bigsuf , c = s[p] - 'a'; while((p-1-tree[cur].len < 0) || s[p - 1 - tree[cur].len] != s[p]) cur = tree[cur].link; if(!tree[cur].go[c]){ int link = tree[cur].link; while((p-1-tree[link].len < 0) || s[p - 1 - tree[link].len] != s[p]) link = tree[link].link; tree[cur].go[c] = ++id; tree[id].go = vi(26,0); tree[id].len = tree[cur].len + 2; tree[id].link = (tree[id].len == 1 ? 2 : tree[link].go[c]); } bigsuf = tree[cur].go[c]; tree[bigsuf].occ ++ ; } int32_t main(){ int t = 1; for(int ii = 0 ; ii < t ; ii ++){ cin >> s; init(); for(int i = 0 ; i < sz(s) ; i++){ append(i); } ll ans = 0; for(int i = id ; i > 2 ; i --){ tree[tree[i].link].occ += tree[i].occ; ans = max(ans , (tree[i].occ * 1ll) * (tree[i].len*1ll)) ; } cout << ans << endl; } } /* clever stuff: * int overflow, array bounds * special cases (n=1?) * do smth instead of nothing and STAY ORGANIZED * Keep it simple stupid * WRITE STUFF DOWN * math -> gcd / lcm / divisors? */
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