이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "meetings.h"
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
const int maxn = 1<<17;
int n, q, h[maxn], l[maxn], r[maxn], P[maxn];
vector<ll> ans;
array<int, 3> tree[2*maxn];
array<int, 3> merge(array<int, 3> a, array<int, 3> b) {
if(a[0] ^ b[0]) return a[0] > b[0] ? a : b;
return {a[0], min(a[1], b[1]), max(a[2], b[2])};
}
void upd(int p, int v) {
p += n;
for(tree[p] = {v, p-n, p-n}; p>>=1;) tree[p] = merge(tree[p<<1], tree[p<<1|1]);
}
array<int, 3> get(int l, int r) {
//cout << l << " " << r << '\n';
array<int, 3> res = {-1, 0, 0};
for(l += n, r += n+1; l < r; l>>=1, r>>=1) {
if(l&1) res = merge(res, tree[l++]);
if(r&1) res = merge(res, tree[--r]);
}
//cout << res[0] << " " << res[1] << " " << res[2] << '\n';
return res;
}
vector<ll> ma[21];
int N[21];
void upda(int t, int p, ll v) {
for(ma[t][p+=N[t]] = v; p>>=1;) ma[t][p] = min(ma[t][p<<1], ma[t][p<<1|1]);
}
ll geta(int t, ll l, ll r) {
ll ans = 1ll<<55;
for(l += N[t], r += N[t]+1; l < r; l>>=1, r>>=1) {
if(l&1) ans = min(ans, ma[t][l++]);
if(r&1) ans = min(ans, ma[t][--r]);
}
return ans;
}
map<pair<int, int>, ll> memo;
ll solve(int l, int r) {
if(r < l) return 0;
if(memo.count({l, r})) return memo[{l, r}];
auto [V, tl, tr] = get(l, r);
ll ans = min({V*1ll*(r-tl+1) + solve(l, tl-1), V*1ll*(tr-l+1) + solve(tr+1, r), V*1ll*(r-l+1) + geta(V, P[tl], P[tr]-1)});
//cout << l << " " << r << " " << V << " " << tl << " " << tr << " / " << ans << '\n';
return memo[{l, r}] = ans;
}
std::vector<long long> minimum_costs(std::vector<int> H, std::vector<int> L,
std::vector<int> R) {
q = L.size();
n = H.size();
for(int i = 0; i < n; i++) {
h[i] = H[i];
l[i] = L[i];
r[i] = R[i];
}
ans.resize(q);
for(int i = 0; i < n; i++) upd(i, h[i]);
vector<int> lst(22, -1);
for(int i = 0; i < n; i++) N[h[i]]++;
for(int i = 1; i <= 20; i++) ma[i].resize(2*N[i]);
vector<int> tcnt(22, 0);
for(int i = 0; i < n; i++) {
P[i] = tcnt[h[i]]++;
if(lst[h[i]] != -1) {
upda(h[i], P[i], solve(lst[h[i]]+1, i-1) - h[i]*1ll*(i - lst[h[i]] - 1));
}
lst[h[i]] = i;
}
for(int i = 0; i < q; i++) ans[i] = solve(l[i], r[i]);
return ans;
}
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