제출 #247018

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
247018		bibabas	Nekameleoni (COCI15_nekameleoni)	C++14	42 / 140	3091 ms	53532 KiB

nekameleoni

#pragma GCC optimize("branch-target-load-optimize,branch-target-load-optimize2,btr-bb-exclusive,-fpeephole2")
#include <bits/stdc++.h>
 
#define ll long long
#define ull unsigned ll
#define vi vector<ll>
#define vvi vector<vi>
#define all(x) x.begin(), x.end()
#define pb push_back
#define mp make_pair
#define ld long double
#define pii pair<ll, ll>
#define mt make_tuple
#define mn(a, b) a = min(a, b)
#define mx(a, b) a = max(a, b)
 
using namespace std;
 
const ll INF = (ll)2e9;
const ll inf = (ll)2e18;
const ld eps = (ld)1e-8;
const ll mod = (ll)10007; 
const ll MAXN = (ll)1e4 + 1;
const ll MAXC = (ll)1e6 + 1;
const ll MAXE = (ll)1000;
const ll MAXLOG = 21;
const ll maxlen = (ll)1e5;
const ll asci = (ll)256;
const ll block = 480;
const ld PI = acos(-1);
const ld e = 2.7182818284;
 
/*#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<
pii,
null_type,
less<pii>,
rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;*/
 
template <class T>
istream& operator >>(istream &in, vector<T> &arr){
    for (T &cnt : arr) {
        in >> cnt;
    }
    return in;
};

ll k;
int used[50], cnt[50];

struct nums{
    vector<pii> p, s;
    ll ans = INF;

    nums() {}
    nums(ll pos, ll x) {
        p.push_back(mp(x, pos));
        s.push_back(mp(x, pos));
    }
    nums(vector<pii> p, vector<pii> s, ll ans): p(p), s(s), ans(ans) {}
};

nums merge(nums a, nums b) {
    vector<pii> p = a.p;
    memset(used, 0, sizeof used);
    for (ll i = 0; i < p.size(); ++i) {
        used[p[i].first] = 1;
    }
    for (ll i = 0; i < b.p.size(); ++i) {
        if (!used[b.p[i].first]) p.push_back(b.p[i]);
        used[b.p[i].first] = 1;
    }
    vector<pii> s = b.s;
    memset(used, 0, sizeof used);
    for (ll i = 0; i < s.size(); ++i) {
        used[s[i].first] = 1;
    }
    for (ll i = 0; i < a.s.size(); ++i) {
        if (!used[a.s[i].first]) s.push_back(a.s[i]);
        used[a.s[i].first] = 1;
    }
    memset(cnt, 0, sizeof cnt);
    ll ost = k;
    ll ans = min(a.ans, b.ans);
    for (ll i = 0; i < b.p.size(); ++i) cnt[b.p[i].first]++, ost--;
    ll l = 0, r = b.p.size() - 1;
    for (; l < a.s.size() && r > -1; ++l) {
        cnt[a.s[l].first]++;
        if (cnt[a.s[l].first] == 1) ost--;
        while (r && cnt[b.p[r].first] > 1) {
            cnt[b.p[r].first]--; r--; 
        }
        if (!ost) ans = mn(ans, b.p[max(r, 0LL)].second - a.s[l].second + 1);
    }
    return nums(p, s, ans);
}

struct stree{
    nums t[400000];

    void build(ll v, ll tl, ll tr, vi &a) {
        if (tl + 1 == tr) {
            t[v] = nums(tl, a[tl]);
            return;
        }
        ll tm = (tl + tr) / 2;
        build(2 * v, tl, tm, a);
        build(2 * v + 1, tm, tr, a);
        t[v] = merge(t[2 * v], t[2 * v + 1]);
    }

    void upd(ll v, ll tl, ll tr, ll pos, ll x) {
        if (tl + 1 == tr) {
            t[v] = nums(pos, x);
            return;
        }
        ll tm = (tl + tr) / 2;
        if (pos < tm) upd(2 * v, tl, tm, pos, x);
        else upd(2 * v + 1, tm, tr, pos, x);
        t[v] = merge(t[2 * v], t[2 * v + 1]);
    }

    ll ans() {
        return t[1].ans;
    }
};

stree t;

void solve() {
    ll n, q; scanf("%d %d %d", &n, &k, &q);
    vi a(n); 
    for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
    for (ll i = 0; i < n; ++i) a[i]--;
    t.build(1, 0, n, a);
    while (q--) {
        ll type; scanf("%d", &type);
        if (type == 1) {
            ll p, v; scanf("%d %d", &p, &v);
            p--, v--;
            t.upd(1, 0, n, p, v);
        } else {
            ll otv = t.ans();
            if (otv == INF) cout << "-1\n";
            else cout << otv << "\n";
        }
    }
}

signed main() {
    srand(time(0));
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
#endif
    cout.precision(30);
    
    solve();
 
    return 0;
}

컴파일 시 표준 에러 (stderr) 메시지

nekameleoni.cpp: In function 'nums merge(nums, nums)':
nekameleoni.cpp:70:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (ll i = 0; i < p.size(); ++i) {
                    ~~^~~~~~~~~~
nekameleoni.cpp:73:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (ll i = 0; i < b.p.size(); ++i) {
                    ~~^~~~~~~~~~~~
nekameleoni.cpp:79:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (ll i = 0; i < s.size(); ++i) {
                    ~~^~~~~~~~~~
nekameleoni.cpp:82:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (ll i = 0; i < a.s.size(); ++i) {
                    ~~^~~~~~~~~~~~
nekameleoni.cpp:89:22: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (ll i = 0; i < b.p.size(); ++i) cnt[b.p[i].first]++, ost--;
                    ~~^~~~~~~~~~~~
nekameleoni.cpp:91:14: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
     for (; l < a.s.size() && r > -1; ++l) {
            ~~^~~~~~~~~~~~
nekameleoni.cpp:97:23: warning: operation on 'ans' may be undefined [-Wsequence-point]
         if (!ost) ans = mn(ans, b.p[max(r, 0LL)].second - a.s[l].second + 1);
                       ^
nekameleoni.cpp: In function 'void solve()':
nekameleoni.cpp:135:42: warning: format '%d' expects argument of type 'int*', but argument 2 has type 'long long int*' [-Wformat=]
     ll n, q; scanf("%d %d %d", &n, &k, &q);
                                ~~        ^
nekameleoni.cpp:135:42: warning: format '%d' expects argument of type 'int*', but argument 3 has type 'long long int*' [-Wformat=]
nekameleoni.cpp:135:42: warning: format '%d' expects argument of type 'int*', but argument 4 has type 'long long int*' [-Wformat=]
nekameleoni.cpp:137:50: warning: format '%d' expects argument of type 'int*', but argument 2 has type '__gnu_cxx::__alloc_traits<std::allocator<long long int> >::value_type* {aka long long int*}' [-Wformat=]
     for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
                                                  ^
nekameleoni.cpp:141:35: warning: format '%d' expects argument of type 'int*', but argument 2 has type 'long long int*' [-Wformat=]
         ll type; scanf("%d", &type);
                              ~~~~~^
nekameleoni.cpp:143:43: warning: format '%d' expects argument of type 'int*', but argument 2 has type 'long long int*' [-Wformat=]
             ll p, v; scanf("%d %d", &p, &v);
                                     ~~    ^
nekameleoni.cpp:143:43: warning: format '%d' expects argument of type 'int*', but argument 3 has type 'long long int*' [-Wformat=]
nekameleoni.cpp:135:19: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     ll n, q; scanf("%d %d %d", &n, &k, &q);
              ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
nekameleoni.cpp:137:38: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
     for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
                                 ~~~~~^~~~~~~~~~~~~
nekameleoni.cpp:141:23: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
         ll type; scanf("%d", &type);
                  ~~~~~^~~~~~~~~~~~~
nekameleoni.cpp:143:27: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
             ll p, v; scanf("%d %d", &p, &v);
                      ~~~~~^~~~~~~~~~~~~~~~~
nekameleoni.cpp: In constructor 'nums::nums()':
nekameleoni.cpp:59:13: warning: branch target register load optimization is not intended to be run twice
     nums() {}
             ^

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