이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <algorithm>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <ratio>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
#include <climits>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/assoc_container.hpp>
// #include <ext/pb_ds/trie_policy.hpp>
#define ll long long
#define ld long double
#define mp make_pair
#define pb push_back
#define in insert
#define vll vector<ll>
#define endl "\n"
#define pll pair<ll,ll>
#define f first
#define s second
#define int ll
#define sz(x) (ll)x.size()
#define all(x) (x.begin(),x.end())
using namespace std;
// using namespace __gnu_pbds;
// typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> os;
const ll INF = 1e12;
const ll N =(22); // TODO : change value as per problem
const ll MOD = 1e9+7;
ll a[N];
ll b[N];
vll nice[N];
bool dp[N][(1ll<<22) + 5];
bool vis[N][(1ll<<22) + 5];
ll n,m;
bool recurse(ll i,ll j){
if(i > n) return 1;
if(vis[i][j]) return dp[i][j];
bool ans = 0;
for(auto k:nice[i]){
if((j&k) == j){
ans |= recurse(i+1,j^k);
}
}
vis[i][j] =1;
return dp[i][j] = ans;
}
void solve(){
cin >> n >> m;
for(int i = 1;i<=n;i++) cin >> a[i];
for(int i= 1;i<=m;i++) cin >> b[i];
sort(a+1,a+n+1);
for(int i =1;i<=n;i++){
ll sum = a[i];
for(int j = 0;j<(1ll<<m);j++){
ll cur = 0;
string bin;
for(int k =0;k<m;k++){
if((j&(1ll<<k))){
cur += b[k+1];
}
}
if(cur == sum) {
nice[i].pb(j);
}
}
}
for(int i =0;i<22;i++){
for(int j= 0;j<(1ll<<21);j++)
vis[i][j] = false;
}
bool gg = recurse(1,0);
if(gg) cout << "YES\n";
else cout << "NO\n";
// cout << recurse(1,0) << endl;
// cout << ans << endl;
}
signed main(){
ios_base::sync_with_stdio(0);
cin.tie(NULL);
ll tt=1;
while(tt--){
solve();
}
}
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