제출 #246307

#제출 시각아이디문제언어결과실행 시간메모리
246307bibabasRelativnost (COCI15_relativnost)C++14
70 / 140
4078 ms49232 KiB
#include <bits/stdc++.h>
 
#define ll long long
#define ull unsigned ll
#define vi vector<ll>
#define vvi vector<vi>
#define all(x) x.begin(), x.end()
#define pb push_back
#define mp make_pair
#define ld long double
#define pii pair<ll, ll>
#define mt make_tuple
#define mn(a, b) a = min(a, b)
#define mx(a, b) a = max(a, b)
 
using namespace std;
 
const ll INF = (ll)2e9;
const ll inf = (ll)2e18;
const ld eps = (ld)1e-8;
const ll mod = (ll)10007;
const ll MAXN = (ll)1e4 + 1;
const ll MAXC = (ll)1e6 + 1;
const ll MAXE = (ll)1000;
const ll MAXLOG = 21;
const ll maxlen = (ll)1e5;
const ll asci = (ll)256;
const ll block = 480;
const ld PI = acos(-1);
const ld e = 2.7182818284;
 
/*#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
typedef tree<
pii,
null_type,
less<pii>,
rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;*/
 
template <class T>
istream& operator >>(istream &in, vector<T> &arr){
    for (T &cnt : arr) {
        in >> cnt;
    }
    return in;
};

ll c = 0;
ll t[400000][21];

void merge(ll v) {
    for (ll i = 0; i <= 20; ++i) t[v][i] = 0;
    for (ll i = 0; i <= 20; ++i) {
        for (ll j = 0; j <= 20; ++j) {
            t[v][min(c, i + j)] += (t[2 * v][i] * t[2 * v + 1][j]) % mod;
            t[v][min(c, i + j)] %= mod;
        }
    }
}

void build(ll v, ll tl, ll tr, vector<pii> &a) {
    if (tl + 1 == tr) {
        t[v][1] = a[tl].first, t[v][0] = a[tl].second;
        return;
    }
    ll tm = (tl + tr) / 2;
    build(2 * v, tl, tm, a);
    build(2 * v + 1, tm, tr, a);
    merge(v);
}

void upd(ll v, ll tl, ll tr, ll pos, pii val) {
    if (tl + 1 == tr) {
        t[v][1] = val.first, t[v][0] = val.second;
        return;
    }
    ll tm = (tl + tr) / 2;
    if (pos < tm) upd(2 * v, tl, tm, pos, val);
    else upd(2 * v + 1, tm, tr, pos, val);
    merge(v);
}

void solve() {
    ll n; cin >> n >> c;
    vector<pii> a(n);
    for (int i = 0; i < n; ++i) {
        cin >> a[i].first;
    }
    for (int i = 0; i < n; ++i) {
        cin >> a[i].second;
    }
    build(1, 0, n, a);
    ll q; cin >> q;
    while (q--) {
        ll pos; pii val; cin >> pos >> val.first >> val.second;
        pos--;
        upd(1, 0, n, pos, val);
        cout << t[1][c] << "\n";
    }
}

int main() {
    srand(time(0));
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#else
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    cout.tie(nullptr);
#endif
    cout.precision(30);
    
    solve();
 
    return 0;
}
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