이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
//#pragma comment(linker, "\stack:200000000")
//#pragma GCC optimize("Ofast")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcount,abm,mmx,avx,avx2,tune=native")
//#pragma GCC target("avx,avx2")
//#pragma GCC target("avx,avx2,fma")
//#pragma GCC optimization("O3")
//#pragma GCC optimization("unroll-loops")
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
#define ll long long
#define ld long double
#define pb push_back
#define fi first
#define se second
#define pii pair<int, int>
#define pll pair<ll, ll>
using namespace std;
using namespace __gnu_pbds;
typedef
tree<
ll,
null_type,
less_equal<ll>,
rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
const int N = 2e3 + 10;
const int mod = 1e9 + 7;
ll n, a[N], dp[N][N];
int main() {
ios_base::sync_with_stdio(NULL); cin.tie(NULL); cout.tie(NULL);
// freopen("input.txt", "r", stdin);
// freopen("input.in", "r", stdin);
// freopen("input.out", "w", stdout);
cin >> n;
for (int i = 1; i <= n; i++)
cin >> a[i];
for (int i = 1; i <= n; i++)
dp[i][1] = max(dp[i - 1][1], a[i]);
ll lim = (n + 1) / 2;
for (int j = 2; j <= lim; j++) {
for (int i = 2 * j - 1; i <= n; i++)
dp[i][j] = max(dp[i - 1][j], dp[i - 2][j - 1] + a[i]);
}
for (int j = 1; j <= lim; j++)
cout << dp[n][j] << "\n";
}
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